Shell Programming and Scripting

When I do the above on directory containing :

daf_2001-03_act.txt
daf_2001-04_act.txt

The content of the files are put on the screen as before.
When I do an ls I get the following files


daf_2001-03_act.txt daf_2001-03_act.txt~ daf_2001-04_act.txt daf_2001-04_act.txt~

As can see there are two new files with a ~ following them. But the filenames are the same.

Hmmm. This is a tough cookie isn't it!

Those files look like temporary files created by a program.
If you want to exclude those files you can extend the grep command e.g.:

Code:

for file in `ls | grep ".*_....-.._.*[^~]$"`
do
  sed 's/\(.*_\)\(.*\)-\(.*\)\(_.*\)/mv & \1\3-\2\4/' "$file"
done

Regards

Firstly thanks to everyone who posted on this thread.
I've finally got it working correctly!!

The code I used is as follows:

Code:

for file in $(ls -1)
do
  newfile="$(echo $file | sed 's/\(.*_\)\(.*\)-\(.*\)\(_.*\)/\1\3-\2\4/')"
  mv $file $newfile
done