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cut - columns with formatted Output

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# 1  
Old 05-16-2008
cut - columns with formatted Output
Hi
I have the input file as below
Code:
***TEST10067
00567GROSZ 099
00567CTCTSDS90
***TEST20081
08233GROZWEWE
00782GWERW899
***TEST30088
08233GROZWEWE
00782GWERW899

I am finding the lines starting with *** and outputing as below
Code:
TEST10067
TEST20081
TEST30088

I need a space between TEST1 and 0067 and similarly for the other records.

grep ^\* 100109.C|cut -c 4-8,' ',9-12
I tried with the above. Is there anyway to format the output with a space.
as i am not getting the desired results.

Regards
Dhana
Last edited by Yogesh Sawant; 05-17-2008 at 06:27 AM.. Reason: added code tags
# 2  
Old 05-17-2008
Code:
$ cat dh.txt
***TEST10067
00567GROSZ 099
00567CTCTSDS90
***TEST20081
08233GROZWEWE
00782GWERW899
***TEST30088
08233GROZWEWE
00782GWERW899

$ sed -n '/^\*/p' dh.txt
***TEST10067
***TEST20081
***TEST30088

$ sed -n '/^\*/p' dh.txt | sed 's/\*\*\*\([A-Z]*\)\([0-9]*\)/\1 \2/'
TEST 10067
TEST 20081
TEST 30088

//Jadu
# 3  
Old 05-17-2008
Might as well condense it into a single sed script.

Code:
sed -n '/^*/!d;s/\*\*\*\([A-Z]*\)\([0-9]*\)/\1 \2/p' dh.txt

# 4  
Old 05-18-2008
cut - output in formatted way
Hi
I got the output as below

$ sed -n '/^*/!d;s/\*\*\*\([A-Z]*\)\([0-9]*\)/\1 \2/p' filename

TEST1 0067*01
TEST2 0081*02
TEST3 0088*03

I need only
TEST1 0067
TEST2 0081
TEST3 0088

and not *01,*02 and *03. I am trying it out.
Meanwhile is there any other simplest way of doing it.

Regards
Dhana
# 5  
Old 05-18-2008
Code:
awk -F"TEST" '/^\*/{split($2,a,"");print FS a[1], a[2]a[3]a[4]a[5]}' filename

# 6  
Old 05-18-2008
ruby one liner
If your input is indeed fixed width, here's a one-liner in ruby:
Code:
$ ruby -e 'STDIN.readlines.each { |l| puts  "#{l[3..7]} #{l[8..-1]}" if l[0..2] == "***"  }' <filename

And the same sort of thing in python:
Code:
python -c 'import sys; print "\n".join([ "%s %s" % (l[3:7], l[8:-1]) for l in sys.stdin.readlines() if l[0:3] == "***" ])' <filename

Or in awk
Code:
awk '/^\*\*\*/ { print(substr($1,4,5),  substr($1,9,10)); }' <filename

--
Q
# 7  
Old 05-19-2008
Hi
The awk looks good to me and i tried changing on it

awk '/^\*\*\*/ { printf "%s %s\n",substr($1,4,5), substr($1,9,4) }' < filename

if my file has the following inputs

***BRRAA0067**
TESTSS
sdfasdf
***SIZZ 0081**
sdfas
sdfasd
***TYPEE0078**
dsfas
asdfasdf

I am getting the below output

BRRAA 0067
SIZZ
TYPEE 0078

If you note that SIZZ has only four characters and a space then i am getting the output as shown above. But i need 0081 also coming up after SIZZ .

Do any one of you have some idea on what needs to be changed ?

REgards
Dhana
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