Compose variable name


 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting Compose variable name
# 1  
Old 05-08-2008
Compose variable name

Hi,

CRT=1
LPORT=
while [ "$LPORT" != "F" ]
do
echo "Please type the Port and F when finish : (current value: $LPORT)"
readDefault -e LPORT
if [ "$LPORT" != "F" ]
then
"LISTEN_PORT"$CRT=$LPORT
$CRT++
fi

done

for i in "$CRT"; do
echo "$LISTEN_PORT$CRT"
done

If I run this I get
./listen.sh: line 32: LISTEN_PORT1=8080: command not found

How should I create that variable and then print it ?

Thanks,
Bianca
# 2  
Old 05-08-2008
Use eval to force the lines to be evaluated twice, once to insert the $CRT value, and a second time to do the assignment or substitution.

Code:
eval "$LISTENPORT"$CRT=$LPORT
...
eval echo "\$LISTEN_PORT$CRT"

Also $CRT++ is not valid shell syntax.
# 3  
Old 05-08-2008
Quote:
Originally Posted by Annihilannic
Use eval to force the lines to be evaluated twice, once to insert the $CRT value, and a second time to do the assignment or substitution.

Code:
eval "$LISTENPORT"$CRT=$LPORT
...
eval echo "\$LISTEN_PORT$CRT"

Also $CRT++ is not valid shell syntax.
This is not working neither:
Please type the Listen Port and F when finish : (current value: 8081)
8082
./listen.sh: line 32: 1+1=8082: command not found
Please type the Listen Port and F when finish : (current value: 8082)
F
+1+1
# 4  
Old 05-08-2008
Ah, apologies, I put in an extra $ by mistake and missed a _.

Code:
eval "LISTEN_PORT"$CRT=$LPORT
...
eval echo "\$LISTEN_PORT$CRT"

This User Gave Thanks to Annihilannic For This Post:
Login or Register to Ask a Question

Previous Thread | Next Thread

9 More Discussions You Might Find Interesting

1. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies

2. Shell Programming and Scripting

[Solved] How to increment and add variable length numbers to a variable in a loop?

Hi All, I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Discussion started by: danish0909
5 Replies

3. Shell Programming and Scripting

awk: compose regex in variable and then use its contents like $0 ~ var

A question to the awk pundits: I was thinking about composing a regex in a variable and then use its contents like $0 ~ var instead of $0 ~ /r/. Sort of indirection. Did someone run into this? Is it possible at all? (3 Replies)
Discussion started by: RudiC
3 Replies

4. Red Hat

How to pass value of pwd as variable in SED to replace variable in a script file

Hi all, Hereby wish to have your advise for below: Main concept is I intend to get current directory of my script file. This script file will be copied to /etc/init.d. A string in this copy will be replaced with current directory value. Below is original script file: ... (6 Replies)
Discussion started by: cielle
6 Replies

5. Shell Programming and Scripting

Variable not found error for a variable which is returned from stored procedure

can anyone please help me with this: i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure... ... (4 Replies)
Discussion started by: swap21783
4 Replies

6. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

7. Shell Programming and Scripting

How to define a variable with variable definition is stored in a variable?

Hi all, I have a variable say var1 (output from somewhere, which I can't change)which store something like this: echo $var1 name=fred age=25 address="123 abc" password=pass1234 how can I make the variable $name, $age, $address and $password contain the info? I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies

8. Shell Programming and Scripting

Insert a line including Variable & Carriage Return / sed command as Variable

I want to instert Category:XXXXX into the 2. line something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong: sed "2i\\${n}Category:$cat\n" Sample: Titel Blahh Blahh abllk sdhsd sjdhf Blahh Blah Blahh Blahh Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies

9. Shell Programming and Scripting

Sed variable substitution when variable constructed of a directory path

Hello, i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem. my var1 is a string constructed like this: filename1 filerev1 filepath1 my var2 is another string constructed like this: filename2 filerev2 filepath2 when i do... (2 Replies)
Discussion started by: alrinno
2 Replies
Login or Register to Ask a Question

Featured Tech Videos