Shell Programming and Scripting

Hello Everyone,

Please help me in finding out the solution.

The problem is .. lets say i have 600 files in a directory. All 600 files are shell script files. Now i need to find out the files which contains a pattern "SHELL" more than once.

No matter how the pattern occurs , it can be in same line or in different lines also.

I hope there must be some fair way to do this. Please help me.

Thanks,

Code:

find /directoryname -name "*.sh" -o -name "any other pattern" | xargs grep -i "SHELL"

or just be in that directory and grep for the pattern

grep "pattern" *

Code:

for file in `ls -1`
do
count=`grep -c "SHELL" $file`
if [ $count -gt 1 ]
then
echo $file 
fi
done

Thank you all for reply.

I will try both solutions.

Thanks,

The first one just greps, the second will list files which don't have any matches at all.

But try this:

Code:

grep -cr SHELL directory | grep -v ':[01]$'

... provided your grep can do -r (recurse a directory).

hello try this one, hope this helped you

find ./ dir_name -exec grep "SHELL" '{}' \; -print;

It seems to me that all the grep solutions that have been posted ignore the requirement of finding the pattern multiple times on the same line.