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matching first instance of FS

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# 1  
Old 04-22-2008
matching first instance of FS
Hi All,

I have a property in a file as:
property=value=a


If I use FS="=" then I want only first = to be considered as field separator and remaining as value
Code:
echo -e "property=value=a" | awk -F= '{print $2}'

ie my $2 should be value=a

Can anyone please help me with this. I need it in awk

Thanks in Advance
Guru
Last edited by Yogesh Sawant; 04-22-2008 at 04:28 AM.. Reason: added code tags
# 2  
Old 04-22-2008
Code:
echo  "property=value=a" | awk -F= '{print $2"="$3}'

or
Code:
echo  "property=value=a" | awk 'BEGIN{FS=OFS="="}{print $2, $3}'

Regards
# 3  
Old 04-22-2008
Thanks for your reply franklin..

I am reading the properties from a file:

so there can be other files with

property=value

in this case I can't print using OFS="=" as there is no 3rd field

How to do in that case
# 4  
Old 04-22-2008
Quote:
Originally Posted by gurukottur
Thanks for your reply franklin..

I am reading the properties from a file:

so there can be other files with

property=value

in this case I can't print using OFS="=" as there is no 3rd field

How to do in that case
In that case:

Code:
awk 'BEGIN{FS=OFS="="}{print $(NF-1), $(NF)}'

Regards
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