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How to Select or cut from the certain filed to the end of the line

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Top Forums Shell Programming and Scripting How to Select or cut from the certain filed to the end of the line
# 1  
Old 04-10-2008
How to Select or cut from the certain filed to the end of the line
Hi:

I have few rows in file..Like suppose...
9063C0 44 00051363603253033253347 3333 070248 06
9063C0 5G PAN00013
9063C0 44 00061030305040404250724 0506 100248 08
9063C0 43 01 00000089

I need to cut the row starting after "9063C0" till the end of the line and store in another file...

My o/P is:
44 00051363603253033253347 3333 070248 06
5G PAN00013
44 00061030305040404250724 0506 100248 08
43 01 00000089
# 2  
Old 04-10-2008
CPU & Memory Use grep and sed combination
Hi Rajesh,


Use grep and sed combinations to do the need.

grep ^9063C0 test | sed 's/^9063C0//'
where test is the file name.

OUTPUT :
===========
$> grep ^9063C0 test
9063C0 44 00051363603253033253347 3333 070248 06
9063C0 5G PAN00013
9063C0 44 00061030305040404250724 0506 100248 08
9063C0 43 01 00000089


$> grep ^9063C0 test | sed 's/^9063C0//'
44 00051363603253033253347 3333 070248 06
5G PAN00013
44 00061030305040404250724 0506 100248 08
43 01 00000089


Hope this is what u wanted......
Last edited by helper; 04-10-2008 at 07:20 AM..
# 3  
Old 04-10-2008
Hi Rajesh,


Use grep and sed combinations to do the need.

grep "9063C0" test | sed 's/9063C0//'
where test is the file name.

OUTPUT :
===========
$> grep ^9063C0 test
9063C0 44 00051363603253033253347 3333 070248 06
9063C0 5G PAN00013
9063C0 44 00061030305040404250724 0506 100248 08
9063C0 43 01 00000089


$> grep ^9063C0 test | sed 's/9063C0//'
44 00051363603253033253347 3333 070248 06
5G PAN00013
44 00061030305040404250724 0506 100248 08
43 01 00000089


Hope this is what u wanted......
# 4  
Old 04-10-2008
Code:
awk '{ $1=""; print }' file

# 5  
Old 04-10-2008
Code:
cut -d" " -f 2- test

# 6  
Old 04-10-2008
Thankx all... Its working.........
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