Shell Programming and Scripting

Hi

I'm not very good with the serach patterns and I'd need a sample how to find a line that has multiple patterns.

Say I want to find a line that has "abd", "123" and "QWERTY" and there can be any characters or numbers between the serach patterns, I have a file that has thousands of lines and each of them can contain one or two of above patterns.

What I want is to print out a line that has all those 3 search patterns.

Thanks,
//Juha

Code:

awk '/123/ && /abd/ && /QWERTY/{print}'  file

It is not clear if you need to check for all the patterns or any of the patterns:

All of them:

Code:

if (/123/ && /abd/ && /QWERTY/) {
    found all patterns
}

any of them:

Code:

if (/123/ ||  /abd/ || /QWERTY/) {
    found one or more patterns
}

Thanks danmero and KevinADC! I took the example from KevinADC as I'm trying to get on top of perl scripting

Look like the OP ask for all patterns on the same line

Yes, but the next sentence makes that ambiguous (to me anyway):

ok.. Let me clarify a little:

Originally I wanted to print a line only if ALL the patterns can be found from that line, so this was ok:

Code:

if (/123/ && /abd/ && /QWERTY/) {
    found all patterns
}

Now, I found a different scenario, which I've tried to figure out... but have to admit that could not..

I'd like to print the line only if I can find "123" and abc", but not "efg":

I thought maybe I could use:

Code:

if (/123/ && /abc/ !& /efg/) {
    found all patterns
}

But !& does not seem to be a valid operator... What would be a way around it?

Thanks.. and sorry for being a bit unclear..