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help with awk delimited by |~| in a record

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# 8  
Old 04-06-2008
Thanks ERA and MATRIXMADHAN.

/usr/local/bin/awk -F"CARDDESC=" '{ split($2, arr, "|"); print arr[1] }' t1
A8T1

now would you be kind enough try to explain what it really did.

I have gone with what matrixmadhan recommended

Peace !!!
# 9  
Old 04-06-2008
Quote:
Originally Posted by era
Whoever devised that particular file format should be taken out and shot.
sometimes, delimiters need to be unique so that it won't get mixed up with actual data in the fields. therefore, you shouldn't jump to conclusions like this Smilie
# 10  
Old 04-06-2008
just another way
Code:
awk -F'[|~=]' '
{
 for ( i =1; i<=NF;i++ ) {
   if ( $i ~ /CARDDESC/ ) {
    print $(i+1)
   }
 }
}' file

# 11  
Old 04-06-2008
Another possibility with sed:

Code:
sed 's/.*ARDDESC=\([^|]*\).*/\1/'

Regards
# 12  
Old 04-06-2008
Quote:
Originally Posted by knijjar
Thanks ERA and MATRIXMADHAN.

/usr/local/bin/awk -F"CARDDESC=" '{ split($2, arr, "|"); print arr[1] }' t1
A8T1

now would you be kind enough try to explain what it really did.

I have gone with what matrixmadhan recommended

Peace !!!

here the field delimiter is CARDDESC=
and within that split the second field ($2) with delimiter as "|" - result is populated in array arr.

Now the result is available at first field of the array
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