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# 1  
Old 04-02-2008
need help for shell programming

My purpose was to print out all of name of students in a list.First of all,I created a file name "List" in /home/tuan/Desktop/Shell_programming as below
Code:
Tom
Henry
Ben
Linda
Marry

And my script "script" is
Code:
#!/bin/sh
path=/home/tuan/Desktop/Shell_programming/List
for student in $path
do 
echo "$student"
done

At terminal I did :
Code:
tuan@tuan:~/Desktop/Shell_programming$ chmod +x script
tuan@tuan:~/Desktop/Shell_programming$ /.script
tuan@tuan:~/Desktop/Shell_programming$ ./script
/home/tuan/Desktop/Shell_programming/List
tuan@tuan:~/Desktop/Shell_programming$

Why after executing, the script displayed
Code:
/home/tuan/Desktop/Shell_programming/List

If I would like to print out the name of student. What should I change the code for my script
# 2  
Old 04-02-2008
First try changing yourself with someone who knows unix-shell before writing shell-scripts or at least someone who learns first and then writes code

Then, maybe change "$path" to `cat $path` in the for-statement
# 3  
Old 04-02-2008
Hammer & Screwdriver suggestion on variable names

I would strongly recommend against using unix keywords as variable names. The word "path" is used for storing locations to find programs for a user. Try typing:
Code:
echo $PATH

to see what I mean.

Yes, uppercase vs. lowercase, but just a matter of there are enough places to make mistakes in unix scripting without causing an extra headache for yourself.

Also, take a look at the following:
Code:
> cat listingnm 
Tom
Henry
Ben
Linda
Marry

Code:
> cat listcontents 
#! /bin/bash

filesrch=listingnm
while read student
   do 
   echo "$student"
done < $filesrch

and the program execution
Code:
> listcontents 
Tom
Henry
Ben
Linda
Marry

# 4  
Old 04-02-2008
@joeyg:thanks for your advice. It is helpful.

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