How to more only the last file in the directory?


 
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# 1  
Old 04-01-2008
How to more only the last file in the directory?

Hi ,

I am writing a script to more the last file (output file) in the specified directory.

Things have to be considered is, the output file written has the time of the file been executed. So i cant seem to more the file by just the hour as thr could be more than 1 file within the same hour.

my script:

dir=/opt/SMAW/INTP/bin

$dir/./sm_tool.sh countRows <--- this line will generate an output to read from. this is a dev script so i wont be able to modify it.

more getRows.info-`date '+%d_%m_%y_%H:%M:%S'` | grep 'SAR' | awk -F" " '$3!=0' | grep -v " versionized" >>
/export/home/rtp99/Tariff


output directory:

-rw-r--r-- 1 rtp99 dba 66249 Sep 19 2007 getRows.info-19_09_07_11:16:11
-rw-r--r-- 1 rtp99 dba 66975 Oct 2 2007 getRows.info-02_10_07_09:55:38
-rw-r--r-- 1 rtp99 dba 66975 Oct 19 17:40 getRows.info-19_10_07_17:37:06
-rw-r--r-- 1 rtp99 dba 66975 Oct 25 13:36 getRows.info-25_10_07_13:33:34
-rw-r--r-- 1 rtp99 dba 67701 Dec 5 10:53 getRows.info-05_12_07_10:50:23
-rw-r--r-- 1 rtp99 dba 67701 Jan 2 17:23 getRows.info-02_01_08_17:20:08
-rw-r--r-- 1 rtp99 dba 67701 Jan 17 10:15 getRows.info-17_01_08_10:13:00
-rw-r--r-- 1 rtp99 dba 70121 Feb 15 10:34 getRows.info-15_02_08_10:31:34
-rw-r--r-- 1 rtp99 dba 70121 Mar 14 10:22 getRows.info-14_03_08_10:19:28
-rw-r--r-- 1 rtp99 dba 70121 Mar 26 13:26 getRows.info-26_03_08_13:22:48
-rw-r--r-- 1 rtp99 dba 70121 Apr 1 00:27 getRows.info-01_04_08_00:23:27
-rw-r--r-- 1 rtp99 dba 70121 Apr 1 15:15 getRows.info-01_04_08_15:11:17

pls ur thoughts.
# 2  
Old 04-01-2008
[code]
more `ls -rt get_rows* | tail -1`
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