Shell Programming and Scripting

this is in one of my scripts...

if ($#argv == 0) then
echo 'blah bla'
exit 0
endif

I want it to be something like this...

if ($#argv == 0 OR $argv >=3)
echo 'blah bla'
exit 0
endif

so when the arguments are none, or greater than three I want this "if then" to take over. how? I guess I could do two if statements, but thats ugly, no??

Hi,
Try out the code given below, I use ksh and It works in that.

#! /bin/sh
if [[ ($# -eq 0) || ($# > 3) ]]
then
echo "blah bla bla"
else
exit
fi

Hope this works for you.

The wretched syntax would seem to indicate that this hapless OP is stuck with csh. ksh idioms do not work in csh.

In both syntaxes, though, the "or" condition is signified with ||

On another note, attempting to script in csh is generally thought to be somewhat misdirected. You might be better off in the long run if you switch to a Bourne-compatible shell for scripting. Google for "csh whynot".

that looks good thank you!

so all the stuff at work is configured with default shell of .csh, is it possible to run a bash script while in a .csh? this is solaris 8 on sun servers....

Yes, the first line of the script (the "shebang" line) indicates what interpreter to use, on modern (post-1979 or so) platforms. It's handled by the kernel, the current shell doesn't care at all.