Perl: finding pattern and substituting


 
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# 1  
Old 03-03-2008
Perl: finding pattern and substituting

In Perl, I know pattern matching is something like, $name =~ /xxxxxx/;
If I find pattern matching using regular expression, how do I substitute it with real string?
For example, I need to find pattern, /-\d\d\d\d/, which is something like "-2000", but those 4 digits can be any numbers.
Now, I need to replace those numbers with "-<certain 4 digit number>".
Is there a way to do it in Perl?
Thank a bunch in advance!!!
# 2  
Old 03-03-2008
Yes -- you use the substitution syntax:

s/<regex you want to find>/<string you want to substitute/

Example: s/matt/MATT/ will substitute "matt" with "MATT."

Incidentally, another way to do your regex would be /-[0-9]{4}/ and you could do your substitution like: s/-[0-9]{4}/string/
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