how to take input at the startup script!!

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# 1  
Old 02-28-2008
how to take input at the startup script!!

Hi all,

I am trying to modify a startup script...
The problem is that i am unable to figure out how to take inputs from the user at the startup screen and proceed with the processing accordingly...

$ echo "this is a test" (typically this would produce the output)...
$ echo "this is a test" >/dev/msglog (this is used to produce the same output before shell is initialized)...

Similarly,i wanted to know the equivalent for the read statement!!!!
$ read x (usually reads <something> to variable x)
How can i incorporate the same at the startup??

# 2  
Old 02-29-2008
something like that ?
while [ "$INPUT_STRING" != "bye" ]
  echo "Please type something in (bye to quit)"
  echo "You typed: $INPUT_STRING"

P.S. I found this on the net.
# 3  
Old 02-29-2008
So you are trying to do something before the system is started?
read var

should work, if not then you could try

or something similar. But in my opinion this is not a good thing.
# 4  
Old 03-01-2008
Yeah something like this, but this is done all the while isnt it??

Eg: During the installation of solaris ,one of the first few screens have this option to choose which type of an installation is to be done!!!
solaris express developer edition
solairs exprees

something like that....
And according to what the user types in the corresponding installation starts up...
SO here the case statement will be used(i supposeSmilie )...
and again the shell isnt initialised yet..
So in this case how does the proper script be recognised...

If i can know how the user input is read here..that would be enough!!!
# 5  
Old 03-02-2008
I'm not understanding if you want to allow a user to give your script a flag/variable at the command line, or if you want an interactive script with a menu. Either way:
Passing a flag/variable to a script, simplest way, in the script just do:

So, when you run the script on the command line, you'd type:
# script.ksh  <myVariable>

The elements in the command line are counted much like the elements in an array, so when you type the above command, script.ksh is $0 , myVariable is $1, whatever you'd type after myVariable is $2, etc.. Quick example:
# cat script.ksh
echo $yourVariable $myVariable

# script.ksh world hello
hello world

You could use $1 in a case statement for an rc startup script, like this:
# cat script.ksh
case $1 in
         start) echo starting;;
          stop) echo stopping;;
             *) echo "don't understand anything but stop and start; doing nothing";;

In the case of an interactive script, when you present users with choices, much like your example of the Solaris installation, if the choices are many and require many words to explained, echo a numbered menu so the user only has to input a number rather than a whole sentence:
# cat script.ksh
echo "Press 1 for start"
echo "Press 2 for stop"
read myVariable?"Enter your choice: "
case $myVariable in
         1) echo starting;;
         2) echo stopping;;
         *) echo "don't understand anything but 1's and 2's; doing nothing";;

Last edited by System Shock; 03-02-2008 at 12:12 PM..
# 6  
Old 03-02-2008
Originally Posted by adderek
But in my opinion this is not a good thing.
I have the same opinion. To the kernel, the definition of a daemon is a process with no controlling terminal. Daemons show up with a ? in the tty field on most implementations of ps. When a daemon opens a tty, that tty becomes it's controlling terminal. It is no longer a daemon nor will any child processes be daemons. As one example of the many problems this will cause, if you type a control c on that terminal all processes with that controlling will get an INTR unless they are ignoring that signal.

You can avoid this by forking a subprocess to open the terminal, do the tty io, pass the data back to the parent via a file or pipe, and then exit. You must also ensure that this is completed prior to any login prompt appearing on the terminal.

This is why daemons fork to write a message on the console. Becoming a daemon again is not possible, but with the right sequence of operations including several forks(), a process can arrange for a descendant process to be created as a daemon.

Avoiding the non-daemon trap will still leave the problem that the user must be present at reboot time, but at least the system should be working.
# 7  
Old 03-02-2008
Thanks a lotSmilieSmilie

I think i can solve the issue with this...
If not i will surely get back...

Thanks again
Smilie Smilie
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