Shell Programming and Scripting

Hello all,

I am having some problems using sed on a sunOS 5.10, I am using bash. For some reason the regexp I am trying to build is not working, even though it should.

I am trying to parse some syslog messages and I need to match the first IP address , then replace it with something else. Does anyone have a quick example of a sed line to match and replace an IP address ?

Thanks,
Sylaan

Show us the sed statement you have.

I just tried something simple first, like matching the first number and replacing it with some text:

Code:

server:~$ echo "This is an IP: 172.10.10.3 " | sed  -e "s/([01]?\d\d)/TEST/g"
This is an IP: 172.10.10.3

But it's not really working. What am I doing wrong ? This is the sed I am using:

Code:

server:~$ which sed
/usr/xpg4/bin/sed

What is ([01]?\d\d) ? That has a Perl resemblance.

Try this one

Code:

sed -e "s/[0-9]\{1,3\}\(\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\)/TEST\1/g"

[0-9]\{1,3\} is used to match numbers from 1 to 999
\. is used to match a '.'

It seems to work, it replaces the first byte of the IP:

Code:

server:~$ echo "This is an IP: 3.10.10.3" | sed -e "s/[0-9]\{1,3\}\(\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\)/TEST\1/g"
This is an IP: TEST.10.10.3

How would I go about replacing the whole IP ?

How do you think that can be done ? Any tries ? I have explained what the regex is.

I think I got it, I need to remove the \1 at the end.