Sort a file line by line alphabetically

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# 8  
Old 02-10-2008
Yes, I asked earlier what you had tried so far. That is quite helpful to the people that reply to you because they can get a feel for where you are going wrong or where you can use improvement and also see what you are doing correct and see what shell script you are using. Next time post any code you had written to try and solve the problem.
# 9  
Old 02-10-2008
Sort line by line

#! /usr/bin/ksh
cat /dev/null > final
while read line_file
echo $line_file | awk '{for (i=1;i<=NF;i++) print $i}' | sort > file_pre
while read line
a=${a}" "${line}
done < file_pre
echo $a >> final
done < $1
cat final


./script file

can be a solution...
# 10  
Old 02-11-2008
a complicate one!!!



Below one can be a solution, but i think it is not good enough.

while read line
	for i in `echo $line`
		echo $i >> temp
	sort temp > temp1
	lnum=`wc -l temp1`
	while [ $i -le $lnum ]
		a=`echo $a" -"`
		i=`expr $i + 1`
	cat temp1 | paste $a >>temp2
	rm temp1
	rm temp
done < filename
cat temp2

# 11  
Old 02-11-2008
#  cat infile
z y x
c b a

#  while read line; do echo $line | tr " " "\n" | sort | tr "\n" " "; echo; done < infile
x y z
a b c

# 12  
Old 02-11-2008
perl -lane'$,=" ";print sort @F' input

GNU Awk:

awk '{split($0,x);asort(x);for(i=1;i<=NF;i++)$i=x[i]}1' input


while read;do print "${(zo)REPLY}";done<input

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