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awk or grep ??


 
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# 1  
Old 01-17-2008
Error awk or grep ??

Hi All,

I need to creat one cutdown file from one full file. The full file may looks as below:

UHL1 08007 DDLIST 000
O301107121212A & L TRANSFER IN ALCB ...................
A301107121212720000IBACS LIAISON ...................
O060807138202B O C THE DIRECT DEBIT DEPT...........
A060605138202404356IBOC MANCHESTER ACC......................
O301106202001ZEUS ADMINISTRATION SERVICES SU BRODIE ....
A301106202001400250IFIRST ADVICE ...................
O060807214209COMMERCIAL UNION LIFE ASSURANCE FRANCIS JACKSON ..................
A060605214209400250ICGU CU CUDDNCS ..............
A060605214209400250ICGU CU CUI-IS DD ..........
O120607232323A & L TRANSFER IN Karina Armstrong ....
A120607232323720000IBACS LIAISON ...................
O130707241010AULD PROPERTIES LTD RAYMOND AULD .......
UTL1064600


I need to extract only lines which starts from "O" to my cutdown file from full file.
Also from this selected lines (which has "O") I need only few position fields.
Position for these fields from full file are (from 8-13),(from 14-30) and (from 36-40).
And each cutdown file record should start with "DTL1".

Finally my cutdown file should look like below:
DTL121212A & L TRANSFER IN ALCB........
DTL1138202B O C THE DIRECT DEBIT DEPT......
.
. etc.,


I know how to select the lines with "O" using grep. But I dont know how to insert DTL1 to each line and also how to select position for this.

I know this can be implemented in awk easily, but Iam not much exposure to awk.

Pls help me achieve this...
# 2  
Old 01-17-2008
Hi,

Am also very new to awk.
But the below command can work out a part of ur query
awk '/^O/ { print "DTL1" $1 }' <filename>
The above command gives the o/p as below:
DTL1O301107121212A
DTL1O060807138202B
DTL1O301106202001ZEUS
DTL1O060807214209COMMERCIAL
DTL1O120607232323A
DTL1O130707241010AULD

As ur file doesnot have any coloumn separator Am not aware of how to print the positional paramaeters.

if there is a space inbetween two strings in a file , then awk consider it as two different arguments.Hence "O301107121212A" is the first argument and "&" "L" "TRANSFER" "IN" "ALCB" are the 2nd 3rd etc arguments.

Regards,
Jisha
# 3  
Old 01-17-2008
There is something wrong with your specification for the fields you want outputted.
Your sample output is variable length but you specify fixed field lengths.
# 4  
Old 01-17-2008
Hope this is what you are looking for...

grep "^O" file | cut -c 8-13,14-30,36-40 | while read line ; do echo DTL1$line ;done

o/p as per your data:
DTL1121212A & L TRANSFER IN ....
DTL1138202B O C THE DIRECT DEPT
DTL1202001ZEUS ADMINISTRATIRVICE
DTL1214209COMMERCIAL UNION ASSUR
DTL1232323A & L TRANSFER INna Ar
DTL1241010AULD PROPERTIES LYMOND


-ilan
# 5  
Old 01-17-2008
Quote:
Originally Posted by ilan
Hope this is what you are looking for...

grep "^O" file | cut -c 8-13,14-30,36-40 | while read line ; do echo DTL1$line ;done

o/p as per your data:
DTL1121212A & L TRANSFER IN ....
DTL1138202B O C THE DIRECT DEPT
DTL1202001ZEUS ADMINISTRATIRVICE
DTL1214209COMMERCIAL UNION ASSUR
DTL1232323A & L TRANSFER INna Ar
DTL1241010AULD PROPERTIES LYMOND


-ilan
Thats perfect ilan.
Thanks
Jisha
# 6  
Old 01-17-2008
And here is the same solution using sed

Code:
sed -n -e 's/\(^O.\{6\}\)\(.\{23\}\)\(.\{5\}\)\(.\{5\}\)\(.*$\)/DTLI\2\4/p' file

# 7  
Old 01-17-2008
Code:
sed -n -e "s/^O.\{6\}\(.\{23\}\).\{5\}\(.\{5\}\).*/DTL1\1\2/p" input.txt

Edit: fpmurphy beat me to it Smilie

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