Shell Programming and Scripting

i have written a script that will grep all the file that run for the current date
i,e today's date

for i in *.log
do
if
a=`date +"%b %d"`

then
ls -ltr | grep $a | tr -s " " | cut -d " " -f6-9
else
echo " "
fi
done
------------------------------------------------------------------------------

these are the apps

-rwxr-xr-x 1 pipe pipe 451 Dec 25 23:54 searchstring
-rwxr-xr-x 1 pipe pipe 179 Dec 26 00:38 filesize
-rwxr-xr-x 1 pipe pipe 89 Dec 26 01:08 revint
-rwxr-xr-x 1 pipe pipe 2126 Jan 9 04:57 wordgame
-rw-r--r-- 1 pipe pipe 1871 Jan 9 06:00 sqlnet.log
-rwxr-xr-x 1 pipe pipe 791 Jan 10 01:24 apps
-rw-r--r-- 1 pipe pipe 1969 Jan 10 01:24 perst
-rw-r--r-- 1 pipe pipe 11020 Jan 10 02:45 core
-rwxr-xr-x 1 pipe pipe 144 Jan 10 03:07 d1
---------------------------------------------------------------------------------------------------------------
i want my script to grep the file according to the current date that is jan 10.the desired o/p should be

Jan 10 01:24 apps
Jan 10 01:24 perst
Jan 10 02:45 core
Jan 10 03:07 d1


---------------------------------------------------------------------

but in this script i cnt grep those files that are running for todays date .its showing me all the file which has benn last modified.

i want to grep only those file which has been modified for current date....plz help me in this

you can use find

Code:

# find . -type f -name "*.log" -mtime -1 -ls

can u please show me the code where to use un my script. actually i m not so aware of unix commands. if u dnt mind can u show me the code

did you try running the find command? you can use back your method , like cut , to get what you want.

its not helping.find is not working...............

i know some problem is there in my ls -ltr logic........can u help me.its showing the previous date o/p also that is yesterday

90113 4 -rwxr-xr-x 1 pipe pipe 791 Jan 10 01:24 ./apps
90114 4 -rw-r--r-- 1 pipe pipe 1969 Jan 10 01:24 ./perst
90116 4 -rwxr-xr-x 1 pipe pipe 179 Jan 10 04:24 ./filesize
90118 4 -rwxr-xr-x 1 pipe pipe 2126 Jan 9 04:57 ./wordgame
90120 4 -rw-r--r-- 1 pipe pipe 1871 Jan 9 06:00 ./sqlnet.log
90121 12 -rw-r--r-- 1 pipe pipe 11020 Jan 10 02:45 ./core
90122 4 -rwxr-xr-x 1 pipe pipe 122 Jan 10 04:26 ./d1

Hi

Try this....


ls -ltr | grep -F "Jan 3" | tr -s " " | cut -d " " -f6-9

Specify the date inside quotes of grep -F.

Or

a=`date "+%b %e"`

ls -ltr | grep -F "$a" | tr -s " " | cut -d " " -f6-9