Shell Programming and Scripting

Sir Ghost,
I thank you for your kindness. Are you a shell programmer? what is your job? Anyway, this is the output that i wanted.

/var/adm/cron/at.allow has the permission 0
/var/adm/cron/cron.allow has the permission 0
/usr/bin/uname has the permission 555
/usr/bin has the permission 755
/dev/mem has the permission 440

$ cat test
/var/adm/cron/at.allow
/var/adm/cron/cron.allow
/usr/bin/uname
/usr/bin
/dev/mem

Code:

while read line 
do
    ls -l $line | awk '
    BEGIN{
    perm["rwx"]=7
    perm["rw-"]=6
    perm["r--"]=4
    perm["-wx"]=3
    perm["--x"]=1
    perm["r-x"]=5
    pern["-w-"]=2
    }
    {
    uperm = substr($1,2,3)
    gperm = substr($1,5,3)
    operm = substr($1,8,3) 
    printf "%s has permission: %s%s%s\n", $9,perm[uperm],perm[gperm],perm[operm]
    }
    '
done < test

stil got no exact results..
this is the result of the said script

users has permission: 555
usrck has permission: 5
utftp has permission: 55
uucp has permission: 55
uudecode has permission: 555
uuencode has permission: 555
uulog has permission: 555
uuname has permission: 55
uupick has permission: 555
uupoll has permission: 555
uuq has permission: 55
uusend has permission: 555
uusnap has permission: 55
uustat has permission: 55
uuto has permission: 555
uux has permission: 55
vacation has permission: 555
val has permission: 555
vc has permission: 555
vedit has permission: 555
vgrind has permission: 755
vi has permission: 555
view has permission: 555
vmh has permission: 555
vmstat has permission: 55
vmstat64 has permission: 55
w has permission: 55
w64 has permission: 55
wait has permission: 555
wallevent has permission: 777
wc has permission: 555
what has permission: 555
whatis has permission: 555
whatnow has permission: 555
whereis has permission: 555
which has permission: 555
who has permission: 555
whoami has permission: 555
whois has permission: 555
whom has permission: 555
wlmmon has permission: 777
write has permission: 555
wsm has permission: 777
xargs has permission: 555
xget has permission: 555
xmodem has permission: 555
xmwlm has permission: 755
xsend has permission: 555
yacc has permission: 777
yes has permission: 555
ypcat has permission: 555
ypmatch has permission: 555
yppasswd has permission: 55
ypservers has permission: 555
ypwhich has permission: 555
zcat has permission: 555
zcmp has permission: 777
zgrep has permission: 777
zmore has permission: 777
znew has permission: 777
2005 has permission: 44

i have left out perm["---"] , you can add it in to represent 0.

sir this is the content of my file name test.

$ cat test
/var/adm/cron/at.allow
/var/adm/cron/cron.allow
/usr/bin/uname
/usr/bin
/dev/mem
/etc/hosts.equiv
/var/adm/sulog
/etc/security/failedlogin
/var/adm/wtmp
/etc/security/lastlog
$

this is the output that i wanted to achieve :

/var/adm/cron/at.allow has the permission 0
/var/adm/cron/cron.allow has the permission 0
/usr/bin/uname has the permission 555
/usr/bin has the permission 755
/dev/mem has the permission 440
/etc/hosts.equiv has the permission 644
/var/adm/sulog has the permission 600
/etc/security/failedlogin has the permission 0
/var/adm/wtmp has the permission 644
/etc/security/lastlog has the permission 0
$

use the perl script then, if you still can't get the results.

yeah i know..thanks, thanks for those who reply.