Parse Line Using Sed


 
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# 1  
Old 12-19-2007
Bug Parse Line Using Sed

Hello All,

I am new to using sed, and I need to extract from the string data after : delimeter.

Can you help me please with the sed command?

Here's the input:
ipAddress: 10.20.10.11
ioIpAddressNodeB: 10.20.10.10
ioIpAddressNodeA: 10.20.10.9
ipAddress: 0.0.0.0

Expected Output:
10.20.10.11
10.20.10.10
10.20.10.9
0.0.0.0

Thanks in advance to anyone who'll reply.

Regards,
racbern
# 2  
Old 12-19-2007
sed 's/.*://g'

should do you

or use awk:

awk '{FS=":";print $2}'

HTH
# 3  
Old 12-19-2007
Here is one way of doing what you want using sed.

Code:
sed -n 's/^.*: \(.*$\)/\1/p'  yourfile

BTW, awk is probably a simpler tool to use for this type of task.

Code:
awk '{ print $2 }' yourfile

# 4  
Old 12-19-2007
Quote:
Originally Posted by fpmurphy
Here is one way of doing what you want using sed.

Code:
sed -n 's/^.*: \(.*$\)/\1/p'  yourfile

BTW, awk is probably a simpler tool to use for this type of task.

Code:
awk '{ print $2 }' yourfile

you forgot the FS definition:
Code:
awk -F: '{ print $2 }' yourfile

# 5  
Old 12-20-2007
Actually no. The -F: option is not required because of the space after the colon on each line.
# 6  
Old 12-20-2007
shell
Code:
#!/bin/sh
while IFS=: read one two
do
    echo $two
done < file

output:
Code:
# ./test.sh
10.20.10.11
10.20.10.10
10.20.10.9
0.0.0.0

# 7  
Old 12-20-2007
awk -F: '{print $2}' file
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