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Show result only if number is greater then

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# 1  
Old 12-05-2007
Show result only if number is greater then
Hello all
Im trying to write one liner that will show me results only if the result of the expression is greater then 0
For example:
I do :
PHP Code:
find . -name "*.dsp" | xargs grep -c SecurityHandler 
the result are : 
 ./foo/blah/a.dsp:0
./foo/blah1/b.dsp:1
./foo/blah2/c.dsp:2
./foo/blah3/d.dsp:0 
Now I like to print only dsp's that the word " SecurityHandler" is more then 0
How can it be done?
# 2  
Old 12-05-2007
Code:
find . -name "*.dsp" | xargs grep -c SecurityHandler  | awk ' !/:0/ { print }'

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