## Problem with IF condition in awk

Problem with IF condition in awk
# 1
11-27-2007
Problem with IF condition in awk

Hi all;

I'm stuck with this simple awk script,i need to group the lines which the position of 28 length 3 that contains "688" into 1 group and other than "688" into another group. My problem is the script only read other than "688" and ignores the lines which contains "688".

The file look like this:
040171011140820070000000009650244002933170003000000075272
1F921338300506 01082007000688jkjddiwe02499834fg
1F921338300506 010820070000198676767675645shdjd
1H912279980109 0108200700009965787889890090uyk
1H912279980109 01082007000688djjdfieuireurireiro

I used this script to group the lines:
Quote:
sort -t" " -rk2.12,2.14 FileLoad.txt |awk '
/^1/ { sub(/1/, "2") }
/^3/ { saved = \$0 }
/^0/ { \$NF = (\$NF FS saved) }
{ x[FNR] = \$0 }
END{
if (substr(x[FNR],1,1)=="0")
print x[FNR]

if(substr(x[j],1,1)!="0" && substr(x[j],28,3)=="688")
{
print 1
for (j=1; j<=FNR; j++)
if(substr(x[j],1,1)!="0" && substr(x[j],28,3)=="688")
print x[j]
}

if(substr(x[j],1,1)!="0" && substr(x[j],28,3)!="688")
{
print 1
for (j=1; j<=FNR; j++)
if(substr(x[j],1,1)!="0" && substr(x[j],28,3)!="688")
print x[j]
}
}'
After execute the script,the output shown:
040171011140820070000000009650244002933170003000000075272
1
2H912279980109 0108200700009965787889890090uyk
2F921338300506 010820070000198676767675645shdjd

can anyone help me to figure out?tq in advance

Last edited by ashikin_8119; 11-27-2007 at 08:49 AM..
 ashikin_8119 View Public Profile for ashikin_8119 Find all posts by ashikin_8119
# 2
11-27-2007
The value of j isn't set before the if statements.

Regards
 Franklin52 View Public Profile for Franklin52 Find all posts by Franklin52
# 3
11-27-2007
awk

Hi, Try this one.

input:
output:
code:
 summer_cherry View Public Profile for summer_cherry Find all posts by summer_cherry

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