Shell Programming and Scripting

Hello I am new to Unix. Please help me out.
My Scenario:
I am first collecting all the file names present in the directory with structure myinfo/yourinfo/supplierinfo
I have four files with the names myCollector.java, yourCollector.java, someCollector.java, everyCollector.java. in the directory.

I am reading the file name and i am getting myinfo/yourinfo/supplierinfo/myCollector.java. and the such string for other files.
I am spliting it to get only substring "myCollector" from the above string which is stored in variable progexe.

How can i access this variable outside awk so that i can run that java class.

#!/bin/bash
source ~/.login
progexearr=""
pruneclass=""
pruneclass="$(find myinfo/yourinfo/supplierinfo -name "*llector.java*")"

echo "$pruneclass"| awk '{
z=split($0,flds," ")
for(i=1;i<=z;i++)
progcompile=flds[i]
p2 = length(progcompile)
exetemp=substr(progcompile,41,p2)
progexe=substr(exetemp,0,length(exetemp)-5)
# Please dont worry about the above code
progexearr[i]=progexe
print progexe # i am getting myCollector, yourCollector,someCollector and everyCollector. How can i access the value of variable and array outside awk.
print progexearr[i]
}'
How can i access value of progexearr array out awk..

somebody please help...

thanks

It looks to me like you could put back ticks (`) around the entire awk statement.
Example:

Code:

echo "some stuff for awk to process" | awk '{ print $2 }'

Prints the string "stuff"
Example of trapping this returned string

Code:

myvariable=`echo "some stuff for awk to process" | awk '{ print $2 }'`
if [ "$myvariable" = "stuff" ]
then
    echo "Yay, we found stuff"
else
    echo "Something went wrong with the script"
fi