Shell Programming and Scripting

Hi

Im running a backup scriptwhich creates a log file

how do grep for the string in the logfile so the backup script can continue to next stage otherwise it will exit

i.e

12:32:53 INF - Client completed sending data for backup

12:33:02 INF - Backup by root on client lonbob04bak using policy Business_Objects_User, sched bus_obj_user: the requested operation was successfully completed.

so want to have something like:


if

[logfile | grep "the requested operation was successfully completed"]

then continue

Code:

if [ `grep "the requested operation was successfully completed" ${LOGFILE}` ]
then
  ... all ok ...
else
  ... gone south ...
fi

Off the cuff, so please test yourself. (just to be sure)

or maybe... u could

grep "the requested operation was successfully completed" logfile > /dev/null
if [ $? -eq 0 ]
then
continue
else
exit
fi

-

#!/bin/ksh

grep "the requested operation was successfully completed" $1 >/dev/null
RESULT =`echo $?`
if [ $RESULT == 0 ]; then
echo "Continue"
else
echo "Stop"
fi

Assume this script file name is sample.sh. If your log file name is logfile, then in the command prompt give like this

$sample.sh logfile

There are several approaches depending on:
- the backup script runs outside your script.
- the backup script finishes when that line is shown inside the log.
- the backup log only has (or will have) one line containing the text.
- others...
One possibility in this case:

Code:

#!/bin/ksh

( tail -f backup.log | while read l; do
   echo ".\c"
   echo $l | grep "the requested operation was successfully completed" > /dev/null 2>&1
   (( ! $? )) && exit 0
done ) && echo "string found, continue..."

# whatever to execute after the match, down here...

At least if you want to check the log file "on the fly"...

Regards.