Extract string between <>


 
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# 8  
Old 11-20-2007
didnt quite work

Quote:
Originally Posted by Franklin52
Code:
DB1=`echo $line | sed 's/.*<\(.*\)> <.*/\1/'`

DB2=`echo $line | sed 's/.*> <\(.*\)>"/\1/'`

Regards
bash-3.00$ line='###Usage: $0 <database1> <database2>'
bash-3.00$ DB1=`echo $line | sed 's/.*<\(.*\)> <.*/\1/'`
bash-3.00$
bash-3.00$ DB2=`echo $line | sed 's/.*> <\(.*\)>"/\1/'`
bash-3.00$ echo $DB1
database1
bash-3.00$ echo $DB2
###Usage: $0 <database1> <database2>
bash-3.00$
# 9  
Old 11-20-2007
Ahh crikey - I just noticed radoulov's post. Good call.

Last edited by LivinFree; 11-20-2007 at 02:58 PM..
# 10  
Old 11-20-2007
Quote:
Originally Posted by rakeshou
bash-3.00$ line='###Usage: $0 <database1> <database2>'
bash-3.00$ DB1=`echo $line | sed 's/.*<\(.*\)> <.*/\1/'`
bash-3.00$
bash-3.00$ DB2=`echo $line | sed 's/.*> <\(.*\)>"/\1/'`
bash-3.00$ echo $DB1
database1
bash-3.00$ echo $DB2
###Usage: $0 <database1> <database2>
bash-3.00$
Though your string was within double quotes, anyway this should work:

Code:
DB2=`echo $line | sed 's/.*> <\(.*\)>/\1/'`

Regards
# 11  
Old 11-20-2007
How about this way using offsets

As an example:

export line="###Usage: \$0 <database1> <database2>"

db1=`echo ${line:14:9}`
db2=`echo ${line:26:9}`

echo $db1
database1

echo $db2
database2

Parameter Substitution and Expansion
http://tldp.org/LDP/abs/html/refcards.html#AEN20323
# 12  
Old 11-20-2007
Bug

you could try this:

DB1=`echo $line | tr '>' ' ' | cut -d "<" -f2`
DB2=`echo $line | tr '>' ' ' | cut -d "<" -f3`

assuming the variable line contains the following in the following format:
line="###Usage: $0 <database1> <database2>"
# 13  
Old 11-20-2007
not exactly

Quote:
Originally Posted by sandy0077
you could try this:

DB1=`echo $line | tr '>' ' ' | cut -d "<" -f2`
DB2=`echo $line | tr '>' ' ' | cut -d "<" -f3`

assuming the variable line contains the following in the following format:
line="###Usage: $0 <database1> <database2>"
bash-3.00$ line='echo "###Usage: $0 <database1> <database2>"'
bash-3.00$ DB1=`echo $line | tr '>' ' ' | cut -d "<" -f2`
bash-3.00$ DB2=`echo $line | tr '>' ' ' | cut -d "<" -f3`
bash-3.00$ echo $DB1
database2 "
bash-3.00$ echo $DB2
database2 "
# 14  
Old 11-20-2007
oh!!
This should work

line='echo "###Usage: $0 <database1> <database2>"'

DB1=`echo $line | tr '>' ' ' |tr '"' ' ' | cut -d "<" -f2`
DB2=`echo $line | tr '>' ' ' |tr '"' ' ' | cut -d "<" -f3`
echo $DB1
echo $DB2
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