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awk user input

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# 1  
Old 10-29-2007
Question awk user input
Using the following I'm trying to print the user's response to the prompt Y / N but I get nothing other than the contents of $1?

awk '{
printf($1 " ? (Y/N)")
getline myresponse < "-"
system("read myresponse")
if (myresponse == "Y")
{ print $1 myfrans }
}' $myfile
# 2  
Old 10-29-2007
Code:
nawk '
  BEGIN {
     printf "Enter your name: "
     getline name < "-"
     print name
}' < /dev/null

This User Gave Thanks to vgersh99 For This Post:
RavinderSingh13
# 3  
Old 10-29-2007
Quote:
Originally Posted by vgersh99
Code:
nawk '
  BEGIN {
     printf "Enter your name: "
     getline name < "-"
     print name
}' < /dev/null

Thanks for the reply but this does not work, I need awk (or nawk) to read a file that contains lines, the user is then shown the line and should enter Y to select it or N to skip. If they select Y it should be written into another file or variable for use later in the script.
# 4  
Old 10-29-2007
nawk -f gefa.awk myInputFile

gefa.awk:
Code:
function promptMe(myLine,   yn)
{
   printf("Select [%s] (Y/N): ", myLine)
   getline yn < "-"

   return tolower(yn)
}
{
  if (promptMe($0) == "y")
     print "do the YES thingy"
  else
     print "do the NO thingy"
}

# 5  
Old 10-29-2007
Thanks, that is better, but still having problems as it displays all lines from myInputFile without prompting. With system("read") I get the prompts but input is ignored?

Quote:
Originally Posted by vgersh99
nawk -f gefa.awk myInputFile

gefa.awk:
Code:
function promptMe(myLine,   yn)
{
   printf("Select [%s] (Y/N): ", myLine)
   getline yn < "-"

   return tolower(yn)
}
{
  if (promptMe($0) == "y")
     print "do the YES thingy"
  else
     print "do the NO thingy"
}

# 6  
Old 10-29-2007
Works fines under Solaris 9 "nawk".
# 7  
Old 10-29-2007
I'm using AIX5.2

Quote:
Originally Posted by vgersh99
Works fines under Solaris 9 "nawk".
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