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Pass csh variable to Perl

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# 1  
Old 10-18-2007
Pass csh variable to Perl
Hi All,

I am trying to put the csh variable into a perl.
In the below case, i am trying to put the csh variable "var" into my perl code. I tried to use '"$var"' but i don;t think it works.

Can anybody help me pls?

Code:
#!/bin/csh

set var = `echo "xxx"`

perl myperlcode.pl file

where the perl code is

Code:
#!/usr/local/bin/perl
$[ = 1;                 # set array base to 1
$, = ' ';               # set output field separator
$\ = "\n";              # set output record separator

line: while (<>) {
    chomp;      # strip record separator
    @Fld = split(' ', $_, 9999);
    if ($Fld[1] eq '**' && $Fld[8] eq '2007' && $Fld[2] =~ /'"$var"'/) {
        print $_;
            }

Input File:

ddddd
ppp
** xxx qqqqq qqq qq qq qq 2007
jjjj
kkkk
lll
ppp


Expected Output:
** xxx qqqqq qqq qq qq qq 2007
# 2  
Old 10-18-2007
Unless you are passing the value as an argument you will most probably have to export it.

Also, in perl try some form of getenv().
# 3  
Old 10-18-2007
Hi Porter,

Can you explain what is meant by passing by arguement? Any examples?

On the export part , any examples?
# 4  
Old 10-18-2007
Quote:
Originally Posted by Raynon
Can you explain what is meant by passing by arguement? Any examples?
just like you did with "file".

Quote:
Originally Posted by Raynon
On the export part , any examples?
apparently "setenv" does the trick.
# 5  
Old 10-18-2007
On the Perl side that is

$ENV{'var'}

Of course you have to export it from the shell for Perl to see it.
# 6  
Old 10-18-2007
Hi cbkihong,

Do you mean the below? I encounter some error though.
I do not know how to export. Can you give me some guidance or show me an example ?

Code:
#!/usr/local/bin/perl
$[ = 1;                 # set array base to 1
$, = ' ';               # set output field separator
$\ = "\n";              # set output record separator

$ENV('var')

line: while (<>) {
    chomp;      # strip record separator
    @Fld = split(' ', $_, 9999);
    if ($Fld[1] eq '**' && $Fld[8] eq '2007' && $Fld[2] =~ /'"$var"'/) {
        print $_;
            }
}

# 7  
Old 10-19-2007
Quote:
Originally Posted by Raynon
Code:
#!/usr/local/bin/perl
$[ = 1;                 # set array base to 1
$, = ' ';               # set output field separator
$\ = "\n";              # set output record separator

$ENV('var')

It's curly braces {}, not parentheses. Please retry, and if there is any errors, please quote them if you post again.
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