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Shell Programming and Scripting

Reference Variable

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# 15  
Old 10-02-2007
shell does not need a break statement like C or C++. With a double ";;" it does not fall into the next case.
# 16  
Old 10-02-2007
Quote:
Originally Posted by porter
shell does not need a break statement like C or C++. With a double ";;" it does not fall into the next case.
... but you need it to exit the select loop:

Code:
zsh 4.3.4% select v in 1 2 3;do
select> case $v in
select case> 1) print $REPLY;;
select case> 2)print $REPLY;; 
select case> esac
select> done
1) 1  2) 2  3) 3  
?# 1
1
?# 2
2
?# 3
?#

Code:
zsh 4.3.4% select v in 1 2 3;do
case $v in
1) print $REPLY;break;;
2)print $REPLY;;
esac
done
1) 1  2) 2  3) 3  
?# 1
1
zsh 4.3.4%

# 17  
Old 10-02-2007
so, to clarify, put the example you supplied into the suggested format:

Code:
select server in  server1 server2;do
        case $server in
                server1) ipaddy="192.168.0.4:21";break;;
                server2) ipaddy="192.168.0.5:990";break;;
                *)printf "Invalid option\n";break;;
        esac
done

ftp username@"$ipaddy"

If the user chose server1 the ftp session is subsequently established with 192.168.0.4 on port 21.
If they chose server2 the ftp session is with 192.168.0.5 on port 990.

Capische? Smilie
# 18  
Old 10-02-2007
Capisce (not capische) chi?

Thank you for teaching me how to explain ... Smilie
# 19  
Old 10-03-2007
MySQL Capische!
The script is working brilliantly!

Thanks everyone for your time and input!
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