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how to cut first 3 characters of each line in a file

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# 1  
Old 04-25-2008
how to cut first 3 characters of each line in a file
Hi Friends

I have a file
like

sample1.txt
------------
10998909.txt
10898990.txt
1898772222.txt
8980000000000.txt

I need to take first 3 characters of each line in a file and i need to print it '
like loop

109
108
189
898

like this

Please help me in this.

Thank you guys
Krish.
# 2  
Old 04-25-2008
Some possibilties:

Code:
cut -c 1-3 < sample.txt

or
Code:
sed 's/\(...\).*/\1/' sample.txt

Code:
awk '{print substr($0,1,3)|' sample.txt

Regards
# 3  
Old 04-25-2008
Another way, you could do the following:

Code:
#!/bin/sh
cat sample1.txt | while read FILE
do
        SUBSTRING=${FILE:0:3}
        echo $SUBSTRING
done

Regards,
Drew
# 4  
Old 04-25-2008
You can also try:

#!/bin/bash
cat sample1.txt| while read line
do
cut -b -3 |tee result.txt
done
# 5  
Old 04-25-2008
Thank you
It help me a lottttttttttttt

Thanks
Krish.
# 6  
Old 01-29-2009
What is the solution in other way?

cat file.dat
abcd2342398472394
xyxz430583490583409583409
qwet403985649056834430

need output as:
2342398472394
430583490583409583409
403985649056834430

- Raveen O.
# 7  
Old 01-29-2009
Got the solution.

awk '{print substr($0,5)}' file.dat

Smilie

-Raveen O.
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