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Count the number of files in a directory

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Top Forums Shell Programming and Scripting Count the number of files in a directory
# 8  
Old 08-16-2007
Hi Matrix,

Some error encountered when using yr code.

$ ls -l *sorts 2>/dev/null | awk '/^-/{c++}END{ print c }'
Ambiguous output redirect
# 9  
Old 08-16-2007
Code:
-rw-r--r--    1 user  grp          0 Aug 16 14:34 asorts
-rw-r--r--    1 user  grp          0 Aug 16 14:34 bsorts
drwxr-xr-x    2 user  grp       4096 Aug 16 14:35 dsorts/

Code:
ls -l *sorts | awk '/^-/{c++}END{ print c}'
2

only count of files [*sorts] is displayed
# 10  
Old 08-16-2007
Code:
find /path -maxdepth 1 -type f -name "*sorts" | wc -l

# 11  
Old 08-16-2007
hi ghostdog,

Some error found when using yr code

$ find /path -maxdepth 1 -type f -name "*sorts" | wc -l
find: bad option -maxdepth
find: path-list predicate-list
0
# 12  
Old 08-16-2007
What's your OS version
# 13  
Old 08-16-2007
MySQL
This is the simple option.

ls -l "directory name" | grep "^-" | wc -l

or

ls -l . | grep "^-" | wc -l

0r

ls -l * | grep "^-" wc -l

or generic could be like this in shell script--

#!/usr/bin/ksh

echo "display the list of files"
ls -ltr

echo "Read the directory in which you want to count the number of files"
read dir

ls -l $dir | grep "^-" | wc -l
# 14  
Old 08-16-2007
Quote:
Originally Posted by Raynon
hi ghostdog,

Some error found when using yr code

$ find /path -maxdepth 1 -type f -name "*sorts" | wc -l
find: bad option -maxdepth
find: path-list predicate-list
0
first, make sure you have /path as a directory?? if not substitute ..however if you don't have the maxdepth option, you can use prune, so that it don't traverse subdirectories (if that's what you want.)
Code:
# find * -type f -name "*sorts"  -print -o -type d -prune |wc -l
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