[grep awk cut] > awk


 
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# 1  
Old 08-02-2007
Bug [grep awk cut] > awk

Hi, I'm very new to scripting.


grep $s $filename | awk '{print $2}' | cut -c 1-8


How can I optimize this using a single awk?

I tried:
awk '/$s/ {print $2}' $filename | cut -c 1-8

However didn't work, I think the awk is not recognizing $s and the verbal is something else.
# 2  
Old 08-02-2007
Can you tell us about your requirement.. What exactly are you trying to do.

Are you looking for something like this
Code:
grep $s $filename| awk '{print substr($2,1,8)}'

# 3  
Old 08-02-2007
May be,
Code:
awk -v var=$s '/$0 ~ var/ {print substr($2,1,8)}' $filename


Last edited by ranj@chn; 08-02-2007 at 03:47 AM.. Reason: typo
# 4  
Old 08-02-2007
Quote:
Originally Posted by lorcan
Can you tell us about your requirement.. What exactly are you trying to do.

Are you looking for something like this
Code:
grep $s $filename| awk '{print substr($2,1,8)}'


further in a single awk

var=some_pattern

( the value of s is assigned here )

Code:
awk -v var=$a '/'$a'/ { print substr($2, 1, 8) }' filename

If not this,

post the sample input and sample output Smilie
# 5  
Old 08-02-2007
Quote:
Originally Posted by firdousamir
Hi, I'm very new to scripting.


grep $s $filename | awk '{print $2}' | cut -c 1-8


How can I optimize this using a single awk?

I tried:
awk '/$s/ {print $2}' $filename | cut -c 1-8

However didn't work, I think the awk is not recognizing $s and the verbal is something else.
Not exactly an awk solution. I believe this should work

Code:
sed -n -e "/$s/s/^[^ ]* \(.\{8\}\).*/\1/p" $filename

# 6  
Old 08-02-2007
Try...
Code:
awk '$0~s {print substr($2,1,8)}' s=$s $filename

# 7  
Old 08-02-2007
Thanks all.

I got the stuff worked. This was my first posting in unix.com. I just loved you people.

Thanks again.
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