cut sed grep or other?

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# 1  
Old 08-01-2007
cut sed grep or other?

Is there a way to cut the last two characters off a word or number given that this word or number can be of varying length?

I have tried something like

TEST=`echo $OLD | cut -c 1-5`

where $OLD is a variable containing a number like 1234567 which gives a result of 12345. This is fine but what if the value of $OLD is longer or shorter?
I only want to always remove the last two digits or characters from a number or a word.
123 becomes 1
12345 becomes 123
1234567 becomes 12345
cold besomes co
hot becomes h


Last edited by rleebife; 08-01-2007 at 09:11 PM..
# 2  
Old 08-01-2007
TEST=`echo $OLD | sed 's/..$//'`

# 3  
Old 08-01-2007
try this

echo please input
read str
echo $str
echo $str | awk '{print substr("'"$str"'",1,length("'"$str"'")-2)}'

# 4  
Old 08-02-2007
# var=12345676776
# echo ${var%*??}

# 5  
Old 08-02-2007
Thanks for your help peeps.. got that workingSmilie
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