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Shell Programming and Scripting

Checking numeric value

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# 1  
Old 05-25-2007
Checking numeric value
Hi,

How can I check numeric value in shell?

I am passing one parameter (integer) and I want to restrict any other characters except 0-9.

./script xyz 10

Here 2nd parameter (10) should be integer only.

Can anyone help on this?

Malay
# 2  
Old 05-25-2007
Code:
if [[ ! -z $(echo $2 | sed 's/[0-9]//g') ]]
then
echo "integer only"; exit
fi

should work
# 3  
Old 05-25-2007
Code:
#echo "1234"  | awk '/^[0-9]+$/' 
1234
#echo "12sasd34"  | awk '/^[0-9]+$/'
#

# 4  
Old 05-25-2007
Oneliner
Here's an oneliner:

awk -v x=$a 'END{if(x==x+0) print "integer"}' /dev/null



In this example , a is shell variable.
If a=10, then the output of above is "integer"
If a="10abhishek", then the output of above is ""
# 5  
Old 05-25-2007
Hello Iam new user , Can help me,
I want get system open file table value , Can u help.

Thanking you,
Mahesh
# 6  
Old 05-25-2007
With bash (extglob option must be on) and ksh :
Code:
if [[ "$var" != +([0-9]) ]]
then
   echo "Not an Integer"
fi


Jean-Pierre.
# 7  
Old 05-25-2007
Quote:
Originally Posted by malaymaru
How can I check numeric value in shell?

I am passing one parameter (integer) and I want to restrict any other characters except 0-9.

./script xyz 10

Here 2nd parameter (10) should be integer only.

Code:
case $2 in
  *[^0-9]*) echo not integer; exit 1 ;;
esac

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