only the pattern in second line "aa" matches and not the one in the first line.
I'm not sure if your response is serious or joking. The OP was looking for a word count. Clearly there are 2 occurrances of aa, but the code counts one. Assuming you are serious, try
I'm not sure if your response is serious or joking. The OP was looking for a word count. Clearly there are 2 occurrances of aa, but the code counts one. Assuming you are serious, try
echo "aa\naa"
I get a blank line.
What is the need for me to joke here ?
Words you have used really have taken me aback.
Ok. coming to the point with your example.
try this first and then the later solution
as per your argument the output should be something like
but the actual output is
so the input string that is matched is "aa<newline>aa<newline>"
and not 'aa' and 'aa' individually
eventually awk will not match the above pattern with 'aa'
and hence there is no effective result.
so the input string that is matched is "aa<newline>aa<newline>"
Thank you. I understand the issue. My point is that the code fails to solve the original problem. It does not count the number of occurrences of the given string. Your posting almost makes it sound like the code is right, so the original problem must be wrong.
sample.txt file:
I'm trying to seperate the occurrences per line by inserting a newline character before and after the word. Once they are newline delimeted, i could grep them to get the total count. however i'm stuck, the \n character does not seem to work...
Hello,
I have a programming assignment to count number of occurrences of hours in particular file. Below is the code:
fname = raw_input("Enter file name: ")
if len(fname) < 1 : fname = "mbox-short.txt"
largest = None
fh = open(fname)
counts = dict()
test = list()
for line in fh:
... (2 Replies)
example:
i have the following text file...
i am very tired.
i am busy
i am hungry
i have to find the number of occurence of a particular word 'am' from the text file.. can any one give the shell script for it (34 Replies)
I have the following string:
31-01-2012, 09:42:37;OK;94727132638;"Mozilla/5.0 (Linux; U; Android 2.2.1)";3G;WAP;I need a script which is counting the occurrence of semicolons ( ; ) but exclude the ones from the quotation marks.
In the string given as example there are 8 semicolons but the script... (3 Replies)
I'm trying to count the number of times each word in the file exist
for example if the file has:
today I have a lot to write, but I will not go for it. The main thing is that today I am looking for a way to get each word in this file with a word count after it specifying that this word has... (4 Replies)
I am a newbie in UNIX shell script and seeking help on this UNIX function. Please give me a hand. Thanks.
I have a large file. Named as 'MyFile'. It was tab-delmited. I am told to write a shell function that counts the number of occurrences of the ord “mysring” in the file 'MyFile'. (1 Reply)
I want to count the number of occurences of say "200" in a file but that file also contains various stuff including dtaes like 2007 or smtg like 200.1 so count i am getting by doing grep -c "word" file is wrong
Please help!!!!! (8 Replies)
Hi all
Can anybody suggest me, how to get the count of digits in a word
I tried
WORD=abcd1234
echo $WORD | grep -oE ] | wc -l
4
It works in bash command line, but not in scripts :mad: (12 Replies)
Greetings,
I need to search and count all the occurences of a word in all the files in a directory.
Any suggestions greatly appreciated.
Thanks (1 Reply)
Hi ,
I am using SUN OS Version 5.6.
I have a file that contains records of length 270. when I do 'set nu' in vi editor, I get the count as 86. whereas when I do "wc -l" on the command prompt, it shows the count as only 85. this is very strange. why would the 'wc' show 1 record less. The job... (3 Replies)