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regexp to get first line of string


 
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# 1  
Old 05-08-2007
Question regexp to get first line of string

Hi everybody

Code:
for file in *
#Bash performs filename expansion
#+ on expressions that globbing recognizes.
do
	
	output="`grep -n "$1" "$file"`"
	echo "$file: `expr "$output" : '\(^.*$\)'`"

done

In the above bash script segment, I try to print just the first line of string named output.

I've got a problem with the regexp. It returns the full string which is multilined.

Thank you in advance for any help
# 2  
Old 05-08-2007
You can try :
Code:
echo ""$file: `echo "$output" | sed -n 1p`"


Jean-Pierre.
# 3  
Old 05-09-2007
Code:
grep -n "$1" "$file" | read output

# 4  
Old 05-09-2007
Thank all of you

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