find pattern and replace another field


 
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# 1  
Old 04-10-2007
Data find pattern and replace another field

HI all

I have a problem, I need to replace a field in a file, but only in the lines that have some pattern, example:

100099C01101C00000000059394200701CREoperadora_TX
100099C01201C00000000000099786137OPERADORA_TX2

in the example above I need to change the first field from 1 to 2 only if the line has the CRE pattern. so the lines will be:

200099C01101C00000000059394200701CREoperadora_TX
100099C01201C00000000000099786137OPERADORA_TX2

Could you help me, how to do this with perl or with awk

Regads

Marcelo
# 2  
Old 04-11-2007
Hi,
Check this code
echo $filename | awk '{if(index($0,"CRE") != 0)
{
if($0 ~ /^1/)
{
printf("2%s\n",substr($0,2,length($0)));
}
else
{
print $0;
}
}
else{print $0}}'

Thanks
Raghuram
# 3  
Old 04-11-2007
Code:
sed "/^1.*CRE/s/^1/2/" file

# 4  
Old 04-11-2007
Quote:
Originally Posted by sergiioo
HI all

I have a problem, I need to replace a field in a file, but only in the lines that have some pattern, example:

100099C01101C00000000059394200701CREoperadora_TX
100099C01201C00000000000099786137OPERADORA_TX2

in the example above I need to change the first field from 1 to 2 only if the line has the CRE pattern. so the lines will be:

200099C01101C00000000059394200701CREoperadora_TX
100099C01201C00000000000099786137OPERADORA_TX2

Could you help me, how to do this with perl or with awk

Code:
awk '/^1.*CRE/ { $1 = "2" substr($1,2) }
                   { print }'

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