checking size of the first line in a log file


 
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# 1  
Old 03-22-2007
checking size of the first line ina file

Hi My test.log file looks like this:
Code:
   0 190_GSTV_HUX_003QISCGSK026_error070322_115331917.log
   34 190_GSTV_HUX_003QISCGSK026_error070117_151311385.log
   12 190_GSTV_HUX_003QISCGSK026_error070117_151230001.log
   2 190_GSTV_HUX_003QISCGSK026_error070117_101010001.log
   0 190_GSTV_HUX_003QISCGSK026_error070117_0832001254.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_122813125.log
   3 190_GSTV_HUX_003QISCGSK026_error070115_115331917.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_114442254.log
   0 190_GSTV_HUX_003QISCGSK026_error070112_1156001509.log

Now i need to write a script which checks for the size of the first log file
ie.,in this case the size of "190_GSTV_HUX_003QISCGSK026_error070322_115331917.log"
please note that the test.log will be updated everytime i run a script and only the part remains constant is '190_GSTV_HUX_003QISCGSK026_errorXXXXXX_XXXXXXXXX.log'

is there any cmd which checks for the size of the first line in the test.log file and give the result?using which i need to write a condition...

Presently i tried this:
Code:
check=`cat /home/user/test.log | awk '{print $1}'`

but it is giving the output as :
0 34 12 2 0 0 3 0 0

if i use the condition
Code:
if [ $check = 0 ]

i m getting error as "A test command parameter is not valid."
beacause check contains 0 32 12 2 ....... Smilie

Please can some one help me in this regard???
Thanks in advance

Last edited by kiran1112; 03-23-2007 at 05:48 AM..
# 2  
Old 03-22-2007
Give a try on this..

Quote:
awk -F" " 'NR==1 {print $1}' filename
Thnx.Dennis
# 3  
Old 03-22-2007
Quote:
is there any cmd which checks for the size of the first line in the test.log file and give the result?using which i need to write a condition...
Code:
awk -F " " '{ print length($2) }' filename


Last edited by matrixmadhan; 03-22-2007 at 05:45 AM.. Reason: should be $2
# 4  
Old 03-22-2007
Quote:
Originally Posted by matrixmadhan
Code:
awk -F " " '{ print length($2) }' filename

Hi Matrix,

Seems like this thread is a continuation of the below thread...I think he is not looking for the size of the second field.....rather, the first field which is the size of the file..

https://www.unix.com/shell-programming-and-scripting/36378-script-check-condition-inside-file.html
# 5  
Old 03-22-2007
how about this,

Code:
ls -l `awk -F" " 'NR == 1 { print $2; exit }' file` | awk '{ print 5 }'

# 6  
Old 03-22-2007
Code:
sed -n -e "s/^ *\([^ ]*\) *.*_error.*/\1/p;q" /home/user/temp.log

# 7  
Old 03-22-2007
Hi all
many thanks for all your suggestions
but none of the commands is able to give the size of only the first line.
the following cmds
Code:
awk -F" " 'NR=1{print $1}' test.log
and 
sed -n -e "s/^ *\([^ ]*\) *.*_error.*/\1/p;"  test.log
and
 ls -l `awk -F" " 'NR == 1 { print $2; exit }' test.log` | awk '{ print 1 }'

gives the first column for all the files...but i only need for the first one Smilie

any help is appreciated
Thanks
Kiran
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