Shell Programming and Scripting

Originally Posted by anbu23

There might be blank lines at the start of test.log file.Remove those blank lines and use

Code:

awk 'NR==1 {print $1;exit}' test.log

but i m writing the script which it clears the existing contents in the test.log file by using the command

Originally Posted by kiran1112

but i m writing the script which it clears the existing contents in the test.log file by using the command

Code:

echo > test.log

Originally Posted by kiran1112

Hi Gurus
My test.log file looks like this:

Code:

   0 190_GSTV_HUX_003QISCGSK026_error070322_115331917.log
   34 190_GSTV_HUX_003QISCGSK026_error070117_151311385.log
   12 190_GSTV_HUX_003QISCGSK026_error070117_151230001.log
   2 190_GSTV_HUX_003QISCGSK026_error070117_101010001.log
   0 190_GSTV_HUX_003QISCGSK026_error070117_0832001254.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_122813125.log
   3 190_GSTV_HUX_003QISCGSK026_error070115_115331917.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_114442254.log
   0 190_GSTV_HUX_003QISCGSK026_error070112_1156001509.log

Now i need to write a script which checks for the size of the first log file
ie.,in this case the size of "190_GSTV_HUX_003QISCGSK026_error070322_115331917.log"
please note that the test.log will be updated everytime i run a script and only the part remains constant is '190_GSTV_HUX_003QISCGSK026_errorXXXXXX_XXXXXXXXX.log'

is there any cmd which checks for the size of the first line in the test.log file and give the result?using which i need to write a condition...

Presently i tried this:

Code:

check=`cat /home/user/test.log | awk '{print $1}'`

but it is giving the output as :
0 34 12 2 0 0 3 0 0

if i use the condition

Code:

if [ $check = 0 ]

i m getting error as "A test command parameter is not valid."
beacause check contains 0 32 12 2 .......

Please can some one help me in this regard???
Thanks in advance