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regular expression for MAC address validation

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Top Forums Shell Programming and Scripting regular expression for MAC address validation
# 15  
Old 03-08-2007
mine is ok, even with backticks.
# 16  
Old 03-08-2007
make sure you have no leading/trailing 'spaces' once you do your 'data entry' - you're anchoring at the beginning and at the end of your 'entered' string.
# 17  
Old 03-08-2007
ive typed it in manually still no good (no spaces at beginning or end).....my script again is ....


Code:
#!/bin/ksh
echo enter mac
read mac
result=$( echo $mac | sed -n "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p" )
if [ -z $result ]; then
  echo mac doesnt comply
else
echo mac is fine
fi


Just out of interest if i run the command that was posted earlier at the command line
Code:
echo 00:60:08:C4:99:AA | sed -n "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p"

i get no output at all ...is this what is expected? ....if i remove the -n at just outputs what ever mac address i put in the begginning of the command (even if its invalid) ie....

Code:
bash # echo sausages | sed "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p"
bash # sausages
bash #

surely that isnt supposed to happen is it ??
# 18  
Old 03-08-2007
OK this works perfectly (using egrep rather than sed)


Code:
#!/bin/ksh
echo enter mac
read mac
result=$( echo $mac | egrep ^[0-9a-f][0-9a-f]\:[0-9a-f][0-9a-f]\:[0-9a-f][0-9a-f]\:[0-9a-f][0-9a-f]\:[0-9a-f][0-9a-f]\:[0-9a-f][0-9a-f]$ )
if [ -z $result ]; then
  echo mac doesnt comply
else
echo mac is fine
fi

# 19  
Old 03-08-2007
Quote:
Just out of interest if i run the command that was posted earlier at the command line
You should get the following output
Code:
$ echo 00:60:08:C4:99:AA | sed -n "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p"
00:60:08:C4:99:AA

Quote:
i get no output at all ...is this what is expected? ....if i remove the -n at just outputs what ever mac address i put in the begginning of the command (even if its invalid) ie....
-n option prevents the default output i.e whatever the string processed by the sed command

Quote:
bash # echo sausages | sed "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p"
bash # sausages
bash #

surely that isnt supposed to happen is it ??
This is correct.
# 20  
Old 03-09-2007
Quote:
Originally Posted by matrixmadhan
You cannot really use nested backticks! Smilie

use this,
Code:
result=$( echo 00:60:08:C4:99:12 | sed -n "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p" )
if [ -z $result ]; then
  echo $result
fi


This was wrong actually as said to ghostdog

check this thread
# 21  
Old 03-09-2007
Quote:
Originally Posted by matrixmadhan
This was wrong actually as said to ghostdog

check this thread
backticks are also viable.
Code:
# result=$( echo 00:60:08:C4:99:12 | sed -n "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p" )
# echo $result
00:60:08:C4:99:12
# result=`echo 00:60:08:C4:99:12 | sed -n "/^\([0-9A-Z][0-9A-Z]:\)\{5\}[0-9A-Z][0-9A-Z]$/p"`
# echo $result
00:60:08:C4:99:12
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