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Please help! Sed extract a pattern

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# 1  
Old 09-14-2006
Please help! Sed extract a pattern
I am trying to extract "securitySettings" out of line:

<a ref ="http://localhost:5654/securitySettings">

using sed as follows:

name = `grep "localhost" file.html | sed -n 's/.*[0-9]*\/\(.*)/\">/\1/p'`

But it didn't run, seems have some syntax error. Do anybody knows why?

Thank you very much!
# 2  
Old 09-14-2006
you missed \ in \(.*\)
unnecessary / in /\">/\1/p
after those modifications
Code:
sed -n 's/.*[0-9]*\/\(.*\)">/\1/p'

Last edited by anbu23; 09-14-2006 at 06:20 PM..
# 3  
Old 09-14-2006
emmmm, why this did not work? it has a ">" at the end of output Smilie Smilie

$ sed 's/^.*:[0-9][0-9]*\/\([^\"]*\)\"\>/\1/' /tmp/test
securitySettings>
# 4  
Old 09-14-2006
Code:
sed -n 's_.*/\([^/]*\)">_\1_p'

# 5  
Old 09-15-2006
CPU & Memory way simpler
can be don in a much more simpler way as follows(i mean there is lesser chance of getting lost in sed Smilie )
Code:
grep "loaclhost" file.html | awk -F'/' '{print $NF }' | sed -e 's/>//g'

hope his works.........do let us know
# 6  
Old 09-15-2006
Quote:
Originally Posted by zhen
I am trying to extract "securitySettings" out of line:

<a ref ="http://localhost:5654/securitySettings">

using sed as follows:

name = `grep "localhost" file.html | sed -n 's/.*[0-9]*\/\(.*)/\">/\1/p'`

But it didn't run, seems have some syntax error. Do anybody knows why?

Thank you very much!
hi , can i clarify , you just want to get "securitySettings" from a line and then assign the value "securitySettings" to a variable called "name" ?

Code:
grep "securitySettings" file.html
if [ $? -eq 0 ]; then
   name='securitySettings'
fi

I think i am missing something...
# 7  
Old 09-15-2006
Quote:
Originally Posted by ghostdog74
hi , can i clarify , you just want to get "securitySettings" from a line and then assign the value "securitySettings" to a variable called "name" ?

I think i am missing something...
he doesnt want to search for securitySettings. Instead he wants to search the word "localhost" and find the last part of that link(href as in a html tag)...
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