Shell Programming and Scripting

Hi, im brasilian, sorry for bad english ok? Well, im writing one honeypot, look:

#!/bin/bash
echo ""
echo `cat /etc/welcome.pot`
echo ""
echo -n "login: "; read usuario
echo -n "Password: "
#stty -echo
read -s senha
#stty echo
exit

Running it in localhost, thats right:

kurumin@servidor:~$ honey.pot

FreeBSD/i386 (servidor) (ttyp0)

login: root
Password:
dear friend, the pass is root, and user root

Good, then I:

$ sudo cat "telnet stream tcp nowait root /usr/bin/honey.pot" >> /etc/inetd.conf

And:

kurumin@servidor:~$ telnet servidor
Trying 127.0.0.1...
Connected to servidor.
Escape character is '^]'.

FreeBSD/i386 (servidor) (ttyp0)

login: root
Password: root

, and user rootpass is root

Two things: The password is not hide and the message in the end.
OK, trying the command stty -echo:

login: root
Password: stty: standard input: Invalid argument

stty: standard input: Invalid argument

What is the problem?? Some in telnet??? I dont know..

Thanks!!

Probably because stty doesn't take effect until you actually log in....
Why are you doing this?
If you are going to create a honeypot, why do you have "honeypot" everywhere in your system?

A honeypot is supposed to be a box that looks and feels like a regular production box, and has hidden ways to track movementnot something that echoes "dear friend, root passwd is root" at login.