Shell Programming and Scripting

Dear "expert",

I need to know the command syntax to get the last field of the line below using shell or awk.

MD5 ("P~04-05-2006~PROPAY_IFT~0662012000750~~PAY2~IFTTEST123~1000.23~~~~AMBB~0012010003406~~~~~~~~~~~~~~~~~~~~~~~A 1234567890B1234567890C1234567890~D1234567890E1234567890F1234567890~G1234567890H1234567890~~") = 0616f08fec37ebf30c1e87cb26e6b200

I expect to have the answer as below
0616f08fec37ebf30c1e87cb26e6b200

Many thanks.

This should work


awk -F"= " '{print $2}' filename

I have tried the AWK script and managed to receive the answer. Thanks.


I would like to find out how to eliminate the left most column which have a space there.

Use the 'tr' command.

Code:

awk -F"= " '{print $2}' filename | tr -d '[:space:]'

The [:space:] will remove any whitespace characters from the line. If you just want to remove ' ' (space) chars, run "tr -d ' '"

Many thanks to you all!!

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