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Unable to print last line in Linux in while loop


 
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# 1  
Old 04-22-2020
Unable to print last line in Linux in while loop

Below is my shell script:

Code:
printf "10\n-rwxr-xr-x 73\n-rwxr-xr-x 74\n10\n-rwxr-xr-x 75\n-rwxr-xr-x 76" |
while IFS=' '
read -r dirn
do
       echo "dirn :"$dirn
done

Output:
Code:
$ ./test.sh
dirn :10
dirn :-rwxr-xr-x 73
dirn :-rwxr-xr-x 74
dirn :10
dirn :-rwxr-xr-x 75

As you can see dirn :-rwxr-xr-x 76 does not get printed.

The exact same code works fine on Aix ksh shell whereas this is bash.

Can you please suggest what is the issue with my code that riun on Linux Redhat bash shell?
# 2  
Old 04-22-2020
Try:
Code:
while IFS='\n'

If that doesnt not fix it, try appending a final character at the end of the line.
As in a tailing "\n" or " " (depends on the IFS you had set).

Hope this helps

Last edited by sea; 04-22-2020 at 07:21 AM.. Reason: removed unwanted space from ifs
# 3  
Old 04-22-2020
The problem is not IFS's contents, which is used as a field separator between the individual fields. Your read is missing the line terminator, usually <LF> (= \n = 0x0A = ^J) which is not printfed. So read waits for it but runs into an EOF / EOT (as stdin terminates), discards the data read so far, and breaks out of the loop having unprocessed data in the variable(s) (Thanks to MadeInGermany's post#5 for mentioning that). You can
- add a linefeed <LF> to the printf command
- switch read to use a different line terminator (which still needs to be printfed). man bash:


Quote:
read
-d delim
The first character of delim is used to terminate the input line, rather than newline.
sea's proposal will set IFS to " ", "\", and "n", split input on any collection of those, and eliminate them from input. Set IFS like IFS=$' \n' to make it <space> and <line feed>.

Last edited by RudiC; 04-25-2020 at 03:59 PM..
# 4  
Old 04-22-2020
Oops..
I just wanted to change to IFS="\n" , not " \n".

Last edited by sea; 04-22-2020 at 07:36 AM..
# 5  
Old 04-25-2020
When read indicates an EOF and the loop ends, it still has read the last incomplete line into the variable.
So you can process it after the loop.
Code:
do_dirn(){
  echo "dirn :$dirn"
}
printf "terminated\nincomplete" |
while
  read -r dirn
do
  do_dirn
done
[ -n "$dirn" ] && do_dirn

This User Gave Thanks to MadeInGermany For This Post:
# 6  
Old 04-30-2020
Would you not be better re-writing the loop to have the loop read the data in rather than have it piped to? That might sound confusingly similar, but some shells will start a sub-process when you add a pipe into it. That might mean that the loop is actually in a sub-process and the scoping of variables may not be what you expect. Of course it might just be that your printf statement doesn't have a new-line after the last item.

Could you consider something like the following instead:-
Code:
while read variable
do
   echo "I got variable ${variable}"
done < <(printf "item1\nitem2\nthird item\last\n")

This runs the process to generate the input in a subshell and your loop runs in the current process so that values might be more what you expect.



I hope that this helps,
Robin

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