How to extract the individual element of array where array is assigned to another variable?

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# 1  
Old 04-14-2020
How to extract the individual element of array where array is assigned to another variable?

I have one file where at every line an array is defined.
a=(1 2 3)
b=(4 5 6)
c=(7 8 9)

I have another file file1.txt where the variables are defined

in the script, I am sourcing the file source file.txt

the script is like

while read -r line           
echo "${!line[*]}"              
done < file1.txt

The output is 0.
Basically, I want to print the individual elements of array defined in file.txt.
source file.txt

How to do that?
# 2  
Old 04-14-2020

You would have better chances with your code, if you would save lists (var="1 2 3")in the file.txt, rather than arrays.
In which case, your code would work just fine - as it is right now.

As a 2nd note, * and @ behave differently for arrays.
Though, you'll get only the first value of an array shown, with this method.

Hope this helps
This User Gave Thanks to sea For This Post:
# 3  
Old 04-14-2020
How to get all the values for array defined in each line?
# 4  
Old 04-14-2020
Perhaps I'm misinterpreting your request but would this suffice?

. ./file.txt
echo "a[1] = ${a[1]} a[2] = ${a[2]}  a[3] = ${a[3]}"
echo "b[1] = ${b[1]} b[2] = ${b[2]}  b[3] = ${b[3]}"
echo "c[1] = ${c[1]} c[2] = ${c[2]}  c[3] = ${c[3]}"

This User Gave Thanks to Chubler_XL For This Post:
# 5  
Old 04-14-2020
I'm afraid you'll have to deploy the dangerous and deprecated eval like

while read -r line           
  do    eval echo "\${!$line[*]}: \${$line[*]}"              
  done < file1.txt
0 1 2: 1 2 3
0 1 2: 4 5 6
0 1 2: 7 8 9

These 2 Users Gave Thanks to RudiC For This Post:
# 6  
Old 04-15-2020
I found one solution.
The space difference between individual elements in file.txt is the key.
while  IFS=" " read -r line
   for i in ${!line}
      echo "$i"
done < "file1.txt"

Thanks everyone for the solutions.
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