Converting seconds to minutes

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# 1  
Old 12-27-2019
Converting seconds to minutes

Hello everyone,

I calculate in my bash script the different between two timestamps in seconds. The next step would be to get the difference in minutes, and there is my Problem:
AnzahlUeberstunden=$(( $(date -d "$JAHR-$MONAT-$TAG $ArbeitEnde" +%s) - $(date -d "$JAHR-$MONAT-$TAG $NormalesArbeitsEnde" +%s) ))

This is the code I calculate the seconds. Normally I would say that I only need to do:AnzahlUeberstunden=$Anzahueberstunden/60 but when I print this I get:2040/60 What am I doing wrong? The count of seconds is right with 2040......

Thanks for all hints


Last edited by rbatte1; 12-30-2019 at 04:56 AM..
# 2  
Old 12-27-2019
Try the same as de line above with $(( ... )) en some corrections in the variable name..

(( AnzahlUeberstunden/=60 ))

# 3  
Old 12-27-2019
Why do i have to put tags around it?
# 4  
Old 12-28-2019
Because it is a an arithmetic operation (you are trying to divide a number by 60)

Therefore you need an arithmetic expansion ( see: Shell command language: arithmetic expansions )
so you can assign the result of the arithmetic expression to a variable (assignment means variable=value)

If you do not do that, in your example AnzahlUeberstunden=$AnzahlUeberstunden/60 what happens is that you assign the value of AnzahlUeberstunden concatenated with the text string /60, so the result becomes 2040/60.

My second suggestion is called an arithmetic expression (which can be used in shells like ksh93, bash, zsh) in which variables can be modified without an explicit variable assignment.

Last edited by Scrutinizer; 12-28-2019 at 03:15 AM..
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# 5  
Old 12-28-2019
look at this way
declare -i AnzahlUeberstunden
AnzahlUeberstunden=$(date -d "$JAHR-$MONAT-$TAG $ArbeitEnde" +%s)-$(date -d "$JAHR-$MONAT-$TAG $NormalesArbeitsEnde" +%s) #"tags" are not needed
AnzahlUeberstunden=AnzahlUeberstunden/60 #dollar sign is not needed
echo $AnzahlUeberstunden

Please note there should not be spaces around the minus sign

Last edited by nezabudka; 12-28-2019 at 09:18 AM..
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# 6  
Old 12-28-2019
Hi Chaos_Lord...

Just an observation; you have shown figures that apparently create a true integer value on integer division...
What happens if the number of seconds is not fully divisible by 60?
Do you just want the integer division, round down and/or round up, or a floating point value?
# 7  
Old 12-29-2019
Originally Posted by nezabudka
Please note there should not be spaces around the minus sign
One could also use quotes:
AnzahlUeberstunden="$(date -d "$JAHR-$MONAT-$TAG $ArbeitEnde" +%s) - $(date -d "$JAHR-$MONAT-$TAG $NormalesArbeitsEnde" +%s)"

AnzahlUeberstunden='AnzahlUeberstunden / 60'

This User Gave Thanks to Scrutinizer For This Post:
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