How to pass and read an array in ksh shell script function.?


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# 1  
How to pass and read an array in ksh shell script function.?

I'm able to read & print an array in varaible called "filelist"

I need to pass this array variable to a function called verify() and then read and loop through the passed array inside the function.

Unfortunately it does not print the entire array from inside the funstion's loop.

Code:
#/bin/ksh
set -A filelist val1 val2 val3
set -A FList

verifyfiles()
{
FList="${1[@]}"

for sym in "${FList[@]}"
do
echo "Array in FUNCTION Contains:"
    echo "$sym"
done
}

verifyfiles $filelist

# 2  
The first posistional parameter is NOT an array, and thus can't be indexed.


How about
Code:
verifyfiles() {  for sym ; do echo "Array in FUNCTION Contains:";     echo "$sym"; done; }
.
.
.
verifyfiles ${filelist[@]}
Array in FUNCTION Contains:
val1
Array in FUNCTION Contains:
val2
Array in FUNCTION Contains:
val3

# 3  
Quote:
Originally Posted by RudiC
The first posistional parameter is NOT an array, and thus can't be indexed.


How about
Code:
verifyfiles() {  for sym ; do echo "Array in FUNCTION Contains:";     echo "$sym"; done; }
.
.
.
verifyfiles ${filelist[@]}
Array in FUNCTION Contains:
val1
Array in FUNCTION Contains:
val2
Array in FUNCTION Contains:
val3

@Rudic thank you for the inputs. How can we assign the passed array to a variable in the function. I ask this becoz i did not get a chance to go back to my system and try out how to do that.
# 4  
If your values will never contain spaces, you can "pass" arrays as strings "val1 val2 val3" and split them back inside the function, like this:

Code:
#!/bin/ksh

set -A filelist val1 val2 val3
set -A otherlist q1 q2 q3

verifyfiles() {
        set -A Flist $1
        set -A Qlist $2
        echo "flist[0]=${Flist[0]}"
        echo "qlist[0]=${Qlist[0]}"
}

verifyfiles "${filelist[*]}" "${otherlist[*]}"

This User Gave Thanks to Corona688 For This Post:
# 5  
Quote:
Originally Posted by Corona688
If your values will never contain spaces, you can "pass" arrays as strings "val1 val2 val3" and split them back inside the function, like this:

Code:
#!/bin/ksh

set -A filelist val1 val2 val3
set -A otherlist q1 q2 q3

verifyfiles() {
        set -A Flist $1
        set -A Qlist $2
        echo "flist[0]=${Flist[0]}"
        echo "qlist[0]=${Qlist[0]}"
}

verifyfiles "${filelist[*]}" "${otherlist[*]}"

Thank you .... Works Perfect @Corona @RudiC.
This User Gave Thanks to mohtashims For This Post:
# 6  
Would name referencing be useful? This is Corona688's solution using namerefs:
Code:
#!/bin/ksh

set -A filelist val1 val2 val3
set -A otherlist q1 q2 q3

verifyfiles() {
   nameref Flist=$1
   nameref Qlist=$2
   echo "flist[0]=${Flist[0]}"
   echo "qlist[0]=${Qlist[0]}"
}

verifyfiles filelist otherlist

As you are passing by reference you can actually change the contents of the original array, which is probably a bad thing.

Andrew
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