Shell Programming and Scripting

Hi,

Try running without the -e switch, it's a long time since I worked on AIX.

As in;

Code:

#!/bin/ksh
VAR1=`echo "${1}" | sed -e "s/'//g"`
echo "${VAR1}" |
  while IFS=' '
read -r dirpath
do
  echo "DIRR_PATH:$dirpath"
  install_dir=$install_dir" "$dirpath
done
echo "Desired Output:$install_dir"

Regards

Gull04

If parameter $1 contains literal \\n then you can use sed to convert to a space

Code:

VAR1=$(printf "%s\n" "$1" | sed 's/\\\\n/ /g')

The \ and \n are really special. Some explanations:
I used ' ' because the shell treats \ literally in them - in contrast to " ".
I used $( ) because the shell does not mistreat \ in them - in contrast to ` `.
I used printf "%s\n" because the ksh builtin echo treats \n in a special way.
Of course I put the $1 in "quotes" to have variable substitution but no further expansions. Note that a literal \ in " " is special but not if it stems from a variable substitution.
So sed sees s/\\\\n/ /g, and treats each \\ as one \

Hi,

Thanks for the detailed explanation, such things are always worth while for mw.

Regards

Gull04

@Gull04 removing -e works. Thank you for the inputs.
@MadeInGermany I will try you suggestions tomorrow.