Extract whole word preceding a specific character pattern with first occurence of the pattern


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# 1  
Extract whole word preceding a specific character pattern with first occurence of the pattern

Hello.


Here is a file contents :
Code:
declare -Ax NEW_FORCE_IGNORE_ARRAY=([FORCE_IGNORE15]="§" [FORCE_IGNORE17]="§" [FORCE_IGNORE1]="§" [FORCE_IGNORE16]="§" [FORCE_IGNORE11]="§" .................. [FORCE_IGNORE23]="§"

Here is a pattern
Code:
=

I want to extract 'NEW_FORCE_IGNORE_ARRAY' which is the whole word before the first occurrence of pattern '='



Is there a better solution than mine :
Code:
MY_PATTERN="="
SOME_VAR=$(cat $SOME_FILE | awk -F$MY_PATTERN '{print $1}' |  awk '{print $3}' )
echo $SOME_VAR

Any help is welcome
# 2  
Hello jcdole,

Yes, that could be shorten to following.
Code:
MY_PATTERN="="
SOME_VAR=$(awk -F"$MY_PATTERN" '{split($1,array," ");print array[3]}' Input_file)
echo "$SOME_VAR"

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 3  
Using built-in parameter substitution:-

Code:
while read line
do
        SOME_VAR="${line%%=*}"
        print "${SOME_VAR##* }"
done < Input_file

This User Gave Thanks to Yoda For This Post:
# 4  
Thank you every body for helping
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