Extract whole word preceding a specific character pattern with first occurence of the pattern

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# 1  
Old 09-18-2019
Extract whole word preceding a specific character pattern with first occurence of the pattern


Here is a file contents :
declare -Ax NEW_FORCE_IGNORE_ARRAY=([FORCE_IGNORE15]="§" [FORCE_IGNORE17]="§" [FORCE_IGNORE1]="§" [FORCE_IGNORE16]="§" [FORCE_IGNORE11]="§" .................. [FORCE_IGNORE23]="§"

Here is a pattern

I want to extract 'NEW_FORCE_IGNORE_ARRAY' which is the whole word before the first occurrence of pattern '='

Is there a better solution than mine :
SOME_VAR=$(cat $SOME_FILE | awk -F$MY_PATTERN '{print $1}' |  awk '{print $3}' )
echo $SOME_VAR

Any help is welcome
# 2  
Old 09-18-2019
Hello jcdole,

Yes, that could be shorten to following.
SOME_VAR=$(awk -F"$MY_PATTERN" '{split($1,array," ");print array[3]}' Input_file)
echo "$SOME_VAR"

R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 3  
Old 09-18-2019
Using built-in parameter substitution:-

while read line
        print "${SOME_VAR##* }"
done < Input_file

This User Gave Thanks to Yoda For This Post:
# 4  
Old 11-09-2019
Thank you every body for helping
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