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Need to split string on single quote as delimiter


 
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# 8  
Quote:
Originally Posted by mohtashims
It works with the below code:

Code:
a=`echo $FPATH | tr "'" "\n" | sed "s/^ //g"`
   for i in "${a[@]}"
do
   printf -- "$i"
done

Thank you everyone for help!!
The correct printf usage is printf "%s\n" "$i".
The format argument not only elimates the problem with a leading - character but also problems with % characters.

printf can apply the format "%s\n" to multiple arguments.
If your loop does only print you can simply do
Code:
a=`echo $FPATH | tr "'" "\n" | sed "s/^ //g"`
printf "%s\n" "${a[@]}"


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