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To print diamond asterisk pattern based on inputs


 
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Top Forums Shell Programming and Scripting To print diamond asterisk pattern based on inputs
# 8  
Old 08-08-2019
Hi C688, Chubler_XL...

Be aware they only work with MIN=1...
Try 'MIN=6' and 'MAX=11'.

I also made the mistake of thinking MIN was also the number of stars in each horizontal plot.

The OP ALWAYS wants a DIAMOND with SINGLE stars, where say the MIN and MAX values of say '3 and 7' give the same results as '4 and 8' or '5 and 9'.

Here is my POSIX update...
Code:
#!/usr/local/bin/dash
# DIAMOND.sh
# POSIX compliant, with no input error checking.
# Using terminal escape codes just for fun.

echo "Enter minimum value:"
read -r MIN
echo "Enter maximum value:"
read -r MAX
printf "\033c\n"
STRNG="* "
STAR="* "
COUNT=1
HORIZ=34
VERT=4
STAR_COUNT=0

STAR="* "
COUNT=${MAX}
while [ ${COUNT} -ge ${MIN} ]
do
    printf "%b" "\033["${VERT}";"${HORIZ}"f${STAR}"
    STAR="${STAR}${STRNG}"
    COUNT=$(( COUNT - 1 ))
    HORIZ=$(( HORIZ - 1 ))
    VERT=$(( VERT + 1 ))
done

HORIZ=34
VERT=$(( VERT + MAX - MIN -1 ))
STAR="${STRNG}"
COUNT=${MAX}
while [ ${COUNT} -ge ${MIN} ]
do
    printf "%b" "\033["${VERT}";"${HORIZ}"f${STAR}"
    STAR="${STAR}${STRNG}"
    COUNT=$(( COUNT - 1 ))
    HORIZ=$(( HORIZ - 1 ))
    VERT=$(( VERT - 1 ))
done

COUNT=$(( MAX - MIN ))
STAR_COUNT=0
while [ ${COUNT} -ge 0 ]
do
    STAR_COUNT=$(( STAR_COUNT + COUNT ))
    COUNT=$(( COUNT - 1 ))
done
STAR_COUNT=$(( ( STAR_COUNT * 2 ) + ( MAX - MIN ) + 1 ))

printf "\033[H"
echo "Number of stars: ${STAR_COUNT}..."

Results using MIN and MAX of 3 and 7, 4 and 8, and 5 and 9.
OSX 10.14.3, default bash terminal calling dash...
Code:
Number of stars: 25...
AMIGA:amiga~/Desktop/Code/Shell> 

                                 * 
                                * * 
                               * * * 
                              * * * * 
                             * * * * * 
                              * * * * 
                               * * * 
                                * * 
                                 *

These 2 Users Gave Thanks to wisecracker For This Post:
# 9  
Old 08-10-2019
wisecracker, your solution in post #8 doesn't seem to match the description (or code) the OP posted.

Testing the original posted code I get:

Code:
enter the mininum number 
3
enter the maximum number 
5
    * * *
   * * * *
  * * * * *
   * * * *
    * * *
Total No. :  19

Can you explain further why you believe '3 and 7' should be giveing the same result as '4 and 8'?
# 10  
Old 08-11-2019
Hi Chubler_XL...
Your quote:
Quote:
Can you explain further why you believe '3 and 7' should be giveing the same result as '4 and 8'?
My quote:
Quote:
I also made the mistake of thinking MIN was also the number of stars in each horizontal plot.
Your quote:
Quote:
Can you explain further why you believe '3 and 7' should be giveing the same result as '4 and 8'?
Because the OP showed a diamond for every valid inputted value, AND, he thanked my post #8.
Also it calls dash so should work on just about any shell.
The code using various values, Linux Mint 19, default terminal calling 'dash'...
Code:
Using 2, 11...
  
Number of stars: 100...
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ 

                                 * 
                                * * 
                               * * * 
                              * * * * 
                             * * * * * 
                            * * * * * * 
                           * * * * * * * 
                          * * * * * * * * 
                         * * * * * * * * * 
                        * * * * * * * * * * 
                         * * * * * * * * * 
                          * * * * * * * * 
                           * * * * * * * 
                            * * * * * * 
                             * * * * * 
                              * * * * 
                               * * * 
                                * * 
                                 * 
Using 1, 10...
The same...

Using 7, 8...
Number of stars: 4...
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ 

                                 * 
                                * * 
                                 * 
Using 1, 2...
The same...

Using 4, 9...
Number of stars: 36...
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ 

                                 * 
                                * * 
                               * * * 
                              * * * * 
                             * * * * * 
                            * * * * * * 
                             * * * * * 
                              * * * * 
                               * * * 
                                * * 
                                 * 
And using 1, 6...
 The same...

AND finally are you sure it was my code you tested because the original version did NOT count the stars, I forgot to add it...
# 11  
Old 08-11-2019
Quote:
Originally Posted by wisecracker
Hi Chubler_XL...
AND finally are you sure it was my code you tested because the original version did NOT count the stars, I forgot to add it...
I was demonstrating how the original code we were asked to simplify in Post #1 works .
I believe this was indicated as doing what was required.


Here is a solution using dash. I make use of a function fill. fill's first argument is the total length of output required and the 2nd (optional) argument specifies the string to use (single space being the default).

As an example fill 3 gives 3 spaces, and fill 5 "AB" gives ABABA.

This function can be used to output a diamond in this fashion:
Code:
fill 3 ; fill 2 '* ' ; echo
fill 2 ; fill 4 '* ' ; echo
fill 1 ; fill 6 '* ' ; echo
fill 0 ; fill 8 '* ' ; echo
fill 1 ; fill 6 '* ' ; echo
fill 2 ; fill 4 '* ' ; echo
fill 3 ; fill 2 '* ' ; echo

And here is the full dash solution using this method:
Code:
#!/bin/dash

fill ()
{
    # fill string to width of count from string chars 
    #
    # usage:
    #      fill count [chars]
    #
    # if count is zero (or less) a blank string is output
    # chars defaults to a space
    #
    local width=$(( ($1) ))
    local str="${2:- }"

    while [ $width -gt 0 ]
    do
        while [ ${#str} -gt $width ]
        do
            str=${str%?}
        done
        width=$((width-${#str}))
        printf "%s" "$str"
    done
}

printf "Enter the mininum number: "
read MIN
printf "Enter the maximum number: "
read MAX

STARS=0
N=$MIN
while [ $N -le $((MAX*2-MIN)) ]
do
    A=$((N-MAX))
    W=$(($MAX-${A#-}))
    fill MAX-W ; fill W*2 '* ' ; echo
    STARS=$((STARS+W))
    N=$((N+1))
done
echo "Total stars: $STARS"


Last edited by Chubler_XL; 08-11-2019 at 07:19 PM..
This User Gave Thanks to Chubler_XL For This Post:
# 12  
Old 08-12-2019
I disagree, the image distinctly shows a DIAMOND, period.
Your code:
Code:
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ ./DIAMOND_CXL.sh
Enter the mininum number: 4
Enter the maximum number: 7
   * * * * 
  * * * * * 
 * * * * * * 
* * * * * * * 
 * * * * * * 
  * * * * * 
   * * * * 
Total stars: 37
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ 

AND

bazza@amiga-MacBookPro:~$ cd Desktop/Code/Shell
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ ./DIAMOND_CXL.sh
Enter the mininum number: -7
Enter the maximum number: -1
      
     
    
   
  
 

 
  
   
    
     
      
Total stars: -55
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$

My code:
Code:
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ ./DIAMOND.sh
Enter minimum value:
-7
Enter maximum value:
-1

Number of stars: 49...
bazza@amiga-MacBookPro:~/Desktop/Code/Shell$ 

                                 * 
                                * * 
                               * * * 
                              * * * * 
                             * * * * * 
                            * * * * * * 
                           * * * * * * * 
                            * * * * * * 
                             * * * * * 
                              * * * * 
                               * * * 
                                * * 
                                 *

So best not to start a flame war and let the OP tell us EXACTLY which one he wants...
This User Gave Thanks to wisecracker For This Post:
# 13  
Old 08-12-2019
I completely agree with your approach which handles all type of scenarios. Thanks guys for your help
These 2 Users Gave Thanks to rohit_shinez For This Post:
# 14  
Old 08-12-2019
Dear All,

All solutions are welcome, not only the original posters request, and thanks to everyone who posted their code and the thoughts behind their design.

Keep those great solutions coming.

Thanks!
This User Gave Thanks to Neo For This Post:

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